A convenience store sells two brands of orange juice Brand A contains 11 fluid once and costs

An unknown capital gets added 5% interest per year by a bank. After how many years does the capital get three times as big, cons

shepuryov [24]

Answer:

After 23 years , the capital will get three times as big

Step-by-step explanation:

Firstly, let us write the compound interest formula

P = I( 1 + r)^n

Since we are considering a capital rise of 3 times

If I, the initial value is x, the P

value later will be 3x

Interest rate is 5/100 = 0.05

so we need the value of t

This will be;

3x = x(1 + 0.05)^t

3= 1.05^t

ln 3 = t ln 1.05

t = ln 3/ln 1.05

t = 23 years

6 0

2 years ago

The angle of parallelogram is 12 less than 5 times the measure of these angle

Y_Kistochka [10]

let one angle be X

so, other angle be 5x-12

ATQ

X+5x-12=180

6x=180-12

6x=168

X=168/6

hence X=28

now,one angle=28

other angle is 5×28-12

= 140-12.

= 128

5 0

2 years ago

Answer ASAP!

valentinak56 [21]

Answer:

A and D

Step-by-step explanation:

Since tangent is opposite/adjacent,

Tan 40 in this case would be x/3.8 (i used x because we don't know what the value is)

So, you set it up as an algebra problem

Tan40 = x/3.8

Multiply both sides by 3.8

3.8tan40 = x, Option A

And then, angle E is 50 degrees

So tan 50 = 3.8/x

Multiply both sides by x

tan50x = 3.8

Divide both sides by tan50

x= 3.8/tan50

So, A and D are both correct

3 0

1 year ago

birute deposite $500 In a savings account with a simple interest rate of 1.3% . how could you use this information to find the i

vladimir2022 [97]

Money Birute deposited in a savings account = $500

Rate of simple interest per annum = 1.3%

▪︎We need to find the interest she will earn in 4 years.

We know that :

$\tt \: \color{hotpink}simple \: interest \color{plum}= \frac{principal \times rate \times time}{100}$

In this case :

Principal = $500

Rate = 1.3%

Time = 4 years

Which means :

The simple interest she will earn in 4 years :

$= \tt \frac{500 \times 1.3 \times 4}{100}$

$= \tt \frac{2600}{100}$

$\color{plum} = \tt\bold{\$26}$

Thus, the simple interest she will earn in 4 years = $26

Amount = Principal + Interest

Amount she will gain after 4 years :

$=\tt 500 + 26$

$\color{plum} = \tt\bold{\$526}$

Thus, the amount she will gain after 4 years = $526

Amount change in her account = 526 - 500 = 26

We know that :

$\tt \: \color{hotpink}percentage \: of \: change\color{plum} = \frac{change}{original \: price} \times 100$

Which means :

Percentage of change in her savings account :

$=\tt \frac{26}{500} \times 100$

$=\tt \frac{26 \times 100}{500}$

$= \tt\frac{2600}{500}$

$\color{plum} = \bold{\tt\bold{5.2\%}}$

<h2>○=> Therefore :</h2>

▪︎Simple interest after 4 years = $26

▪︎Money she will earn after 4 years = $526

▪︎Percentage of change in her savings account = 5.2%

6 0

2 years ago

Each year, all final year students take a mathematics exam. It is hypothesised that the population mean score for this test is 1

Yuri [45]

Answer:

90% confidence interval for the population mean test score is [95.40 , 106.59]

Step-by-step explanation:

We are given that the population mean score for mathematics test is 115. It is known that the population standard deviation of test scores is 17.

Also, a random sample of 25 students take the exam. The mean score for this group is 101.

The, pivotal quantity for 90% confidence interval for the population mean test score is given by;

P.Q. = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, X bar = sample mean = 101

$\sigma$ = population standard deviation

n = sample size = 25

So, 90% confidence interval for the population mean test score, $\mu$ is ;

P(-1.6449 < N(0,1) < 1.6449) = 0.90

P(-1.6449 < $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.6449) = 0.90

P(-1.6449 * $\frac{\sigma}{\sqrt{n} }$ < ${Xbar-\mu}$ < 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ) = 0.90

P(X bar - 1.6449 * $\frac{\sigma}{\sqrt{n} }$ < $\mu$ < X bar + 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ) = 0.90

90% confidence interval for $\mu$ = [ X bar - 1.6449 * $\frac{\sigma}{\sqrt{n} }$ , X bar + 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ]

= [ 101 - 1.6449 * $\frac{17}{\sqrt{25} }$ , 10 + 1.6449 * $\frac{17}{\sqrt{25} }$ ]

= [95.40 , 106.59]

Therefore, 90% confidence interval for the population mean test score is [95.40 , 106.59] .

7 0

3 years ago