The initial value of the linear relationship is 5.
Solution:
- The y-intercept is the point where the line crosses at y-axis.
- The initial value of the linear function is the y-intercept.
On observing the graph, the line crosses y-axis at the point (0, 5).
So, y-intercept = 5
That is initial value = 5
Therefore the initial value of the linear relationship is 5.
In order to utilize the graph, first you have to distinguish which graph accurately pertains to the two functions.
This can be done by rewriting the equations in the form y = mx + b which can be graphed with ease; where m is the slope and b is the y intercept.
-x^2 + y = 1
y = x^2 + 1
So this will be a basic y = x^2 parabola where the center intercepts on the y axis at (0, 1)
-x + y = 2
y = x +2
So this will be a basic y = x linear where the y intercept is on the y axis at (0, 2)
The choice which depicts these two graphs correctly is the first choice. The method to find the solutions to the system of equations by using the graph is by determining the x coordinate of the points where the two graphed equations intersect.
If I understand the question, you have to get n alone. in this case, you have to subtract 7 from both sides, resulting in n (is less than) -10
A counterexample for the statement 'All square roots are irrational numbers.' is the square root of 9. This is because when simplified, the answer is 3.
For a number to be irrational, it can't be expressed in fractional form. However, 3 can be expressed in fractional form as 3/1.
Answer:
A.
I say this is the answer because if she has gotten into a habait of buying and breaking glasses,shes just very careless
