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3 years ago

What is the slope intercept form of the equation of the line shown below

Mathematics

2 answers:

Orlov [11]3 years ago

7 0

Answer:

y = 4/3x -4

Step-by-step explanation:

First find the slope

m = ( y2-y1)/(x2-x1)

= ( 0 - -4)/( 3 - 0)

= (0+4)/( 3-0)

= 4/3

The y intercept is -4

The slope intercept form of the equation is

y = mx+b where m is the slope and b is the y intercept

y = 4/3x -4

omeli [17]3 years ago

4 0

Answer:

$y=\frac{4}{3}x-4$

Step-by-step explanation:

----------------------------------------

The slope-intercept form formula is: $y=mx+b$

The $m$ stands for the slope and the $b$ stands for the y-intercept.

By looking at the graph, I can figure out that the y-intercept is -4 because y-intercept is where the lines cross the y-axis and in this graph, the line crosses the y-axis at (0,-4).

The slope is $\frac{4}{3}$ because to get to the ordered pair (3,0), from (0,-4), you would have to go up 4 and over 3 to the right so it's $\frac{4}{3}$

So now, if we insert the values in the formula, it would be $y=\frac{4}{3}x-4$

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Hope this is helpful.

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Taken together, we find that (0, 0, 0) appears to be the only critical point on $f$ within the ball. At this point, we have $f(0,0,0)=0$ .

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$L_x=5yz+2\lambda x=0$
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$5yz+2\left(-\dfrac{15xyz}2\right)x=0\implies5yz(1-3x^2)=0\implies x=\pm\dfrac1{\sqrt3}$
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