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1 year ago

What is the midpoint of (-1,1) and (-6,3)

Mathematics

1 answer:

Radda [10]1 year ago

6 0

The midpoint of the line segment joining the two points as given in the task content is; (-7/2, 2).

<h3>What is the midpoint of the two points given in the task content?</h3>

According to the task content, the two points given whose midpoint is to be determined are; (-1,1) and (-6,3).

It therefore follows from geometry that the midpoint of the two points can be determined as follows;

x- and y-coordinate of the midpoint can be determined as follows;

x = (x1 + x2)/2

y = (y1 + y2)/2

Hence, the coordinates of the midpoint upon substitution of values are such that;

Midpoint, M = ((-1+(-6))/2 , (1+3)/2)

M = (-7/2, 2)

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2 years ago

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kirill [66]

Answer:

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General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

$\displaystyle y = \frac{3}{2x^2}$

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[Function] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y = \frac{3}{2}x^{-2}$
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Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{-3}{x^3}$

Step 3: Solve

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Evaluate exponents: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1}$
Divide: $\displaystyle y'(1, \frac{3}{2}) = -3$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

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