The derivative is the gradient.
At any local Max's or min's the derivative graph will cut the x axis.
For example a graph x^2
The derivative will have a positive gradient as the gradient is increasing at the lower values then at x=0 the gradient is 0 so the derivative graph will pass the point (0,0). Remember that the derivative graph will be linear.
To get more detail find the points the graph crosses the x axis and put into for a(x-q)(x-p)=0 you will have to solve for 'a' by finding a point on the graph and substituting it in. Then you can find the derivative of that function and graph it
Answer:
Step-by-step explanation:
Because of the nature of the information we are given, we have no choice but to use the equation

and solve for a.
We know by the info that the vertex is (0, 84). We also know that if the vertex is at the origin, and that the base is 42 feet wide, it spans 21 feet to the right of the origin and 21 feet to the left of the origin. That means that we have 2 coordinates from which we need to pick one for our x and y in the equation. I don't like negatives, so I am going to choose the coordinate (21, 0) as x and y. Because this parabola opens upside down, as archways of door openings do, our "a" value better come out algebraically as a negative. Let's see...From the vertex we have that h = 0 and k = 84. So filling in:
and simplifying a bit:
0 = 441a + 84 and
-84 = 441a so
Good, a is negative. Your equation is, then:

thanks for your help I really think that it's three
Answer:
c
Step-by-step explanation:
took test