All categories

1 year ago

1. Henri cut a rope into two pieces with lengths having a ratio of 5 to 2. The shorter piece is

Mathematics

1 answer:

ruslelena [56]1 year ago

8 0

The length of the shorter rope is 20 cm.

<h3>How to find the original length of the rope using ratio?</h3>

He cut a rope into two pieces with lengths having a ratio of 5 to 2.

The shorter piece is 70 cm long.

The length of the original rope can be calculated as follows:

The ratio of the length of the rope is as follows;

5 : 2

let

x = length of the original rope

Therefore,

length of shorter piece = 2 / 7 × 70

length of shorter piece = 140 / 7

length of shorter piece = 20 cm

Therefore, the length of the shorter rope is 20 cm.

learn more on ratio here: brainly.com/question/15418103

#SPJ1

You might be interested in

What is the value of x in the figure?<br> NEED HELP ASAP

Daniel [21]

Answer:

150 degrees

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

This Question: 1 pt

Bezzdna [24]

Answer:69.420

Step-by-step explanation:

I just want points

8 0

2 years ago

Joe has fraction 5 over 6 pound of bird seed. He needs fraction 1 over 3 pound to feed the birds daily. Which of the rectangle m

agasfer [191]

Can someone help me out 4. Normal body temperature is 98.6 degrees Fahrenheit, although it varies slightly for some people.

6 0

2 years ago

Click on all the points that are solutions to y = x^2 - 9.

Oliga [24]

9514 1404 393

Answer:

B) (2, -5)

D) (3, 0)

Step-by-step explanation:

I find it convenient to let a graphing calculator plot the points and the graph.

The only two points on the graph of the curve are ...

(2, -5) and (3, 0)

3 0

3 years ago

Find the exact value of sin2 theta given sin theta =5/13, 90°<theta <180°

Zepler [3.9K]

Now, we know that 90°< θ <180°, that simply means the angle θ is in the II quadrant, where sine is positive and cosine is negative.

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{13}}\impliedby \textit{now let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm\sqrt{13^2-5^2}=a\implies \pm\sqrt{144}=a\implies \pm 12 =a \implies \stackrel{II~quadrant}{-12=a}
\\\\\\
therefore \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{-12}}{\stackrel{hypotenuse}{13}}
\\\\
-------------------------------\\\\
sin(2\theta )\implies 2sin(\theta )cos(\theta )\implies 2\left(\frac{5}{13} \right)\left( \frac{-12}{13} \right)\implies -\cfrac{120}{169}$

3 0

3 years ago