Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
The answer is
T2=(P2V2/T1)/P1V1
Answer:
34 eggs are expected to be used tomorrow
30% of 48 = 14
48-14=34
Step-by-step explanation:
Answer:
C: Charles
Step-by-step explanation:
165 miles divided by 6 hours
165/2.5
66 miles in one hour
Let one acute angle be X and one be Y
X+Y=90 -------Eq.1
2X+12=Y
2X-Y=-12------Eq.2
solving eq 1&2 we get,
3x=78
∴X=26
substituting value X in equation.1
X+Y=90
Y=90-26
∴Y=64
⇒answer:- X=26°
Y=64°
