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Ede4ka [16]
2 years ago
10

Solve the system using substitution

Mathematics
1 answer:
matrenka [14]2 years ago
5 0
I could send you a link on insta
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This is due like right now, please help me!!!!
Varvara68 [4.7K]

\bold{\huge{\orange{\underline{ Solution }}}}

\bold{\underline{ Given \: Rules}}

  • <u>The </u><u>sum</u><u> </u><u>of </u><u>the </u><u>number </u><u>in </u><u>each </u><u>of </u><u>the </u><u>four </u><u>rows </u><u>is </u><u>the </u><u>same </u>
  • <u>The </u><u>sum </u><u>of </u><u>the </u><u>numbers </u><u>in </u><u>each </u><u>of </u><u>the </u><u>three </u><u>columns </u><u>is </u><u>the </u><u>same</u>
  • <u>The </u><u>sum </u><u>of </u><u>any </u><u>row </u><u>does </u><u>not </u><u>equal </u><u>the </u><u>sum </u><u>of </u><u>any </u><u>column </u>

\bold{\underline{ Let's \: Begin}}

<u>According </u><u>to </u><u>the </u><u>Second</u><u> </u><u>rule </u><u>:</u><u>-</u>

\sf{ 75+b+83=76+80+d=a+81+85+78+c+e }

\sf{ 158 + b = 156 + d = 166 + a = 78 + c + e ...(1)}

<u>According </u><u>to </u><u>the </u><u>first </u><u>rule </u><u>:</u><u>-</u><u> </u>

\sf{ 75+76+a+78 = b+80+81+c = 83+86+d+e}

\sf{ 229 + a = 161 + b + c = 168 + d + e ...(2)}

<u>From </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>we </u><u>got </u><u>:</u><u>-</u>

\sf{ 158 + b = 166 + a, 156 + d = 166 + a }

\sf{ b = 166 - 158 + a,  d = 166 - 156 + a }

\sf{ b = 8 + a,  d = 10 + a ...(3)}

<u>Subsitute </u><u>(</u><u>3</u><u>)</u><u> </u><u>in </u><u>(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>:</u><u>-</u>

\sf{229+a = 161+8+a+c = 168+10+a+e}

\sf{ 229+a = 169+a+c = 178+a+e}

<u>We</u><u> </u><u>can </u><u>write </u><u>it </u><u>as </u><u>:</u><u>-</u>

\sf{ 229+a = 169+a+c \:or\:229+a = 178+a+e}

\sf{ c = 299-169+a-a\:or\:e = 229-178+a-a}

\sf{ c = 60 \: and \: e = 51 }

<u>Subsitute </u><u>the </u><u>value </u><u>of </u><u>c </u><u>and </u><u>e </u><u>in </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>

\sf{ 158 + b = 156 + d = 166 + a = 78 + 60 + 51 }

\sf{ 158 + b = 156 + d = 166 + a = 189}

<u>Now</u><u>, </u>

\sf{ For \: b,  158 + b = 189 }

\sf{ b = 189 - 158 }

\sf{ b = 31}

\sf{ For \: d ,  156 + b = 189 }

\sf{ d = 189 - 156 }

\sf{ d = 33}

\sf{ For \: a,  166 + a = 189 }

\sf{ a = 189 - 166 }

\sf{ a = 23 }

Hence, The value of a, b, c, d and e is 23, 31 ,60 ,33 and 51 .

8 0
2 years ago
Work this out for points
KengaRu [80]

Answer:

oh god

Step-by-step explanation:

(2 + 6/2, 7 + 3/2)

=(4 , 5)

3 0
3 years ago
Please help I will reward point and hearts
Mashcka [7]
Fourths, then b. Sorry if late.
5 0
3 years ago
An electronic device factory is studying the length of life of the electronic components they produce. The manager takes a rando
alisha [4.7K]
The answer is B because if you have 10000 hours you subtract by 3000 and it’s equals b
6 0
2 years ago
*50 POINTS -- FRESHMEN ~ ALGEBRA I *
aniked [119]

Step-by-step explanation:

so we know X= Numbers of Large boxes and Y= Numbers of Small boxes

And we know the large boxes weigh <em>7</em><em>5</em><em><u> </u></em><em><u>pounds</u></em> and the small boxes weigh <em>4</em><em>0</em><em> </em><em><u>pounds</u></em>

So I would have to say the the same except you have to flip the inequality sign like this:

75x + 40y

\geqslant  \\

200

And if that doesnt somehow work and the question is wording it wrong then

My guess for why its wrong us because its not in slope intercept form Although you still can solve for either varible ( x or y) using standard form also.

So to get from standard form to Slope intercept form (y=mx+b) these are the steps:

Ax+by=C

75x + 40y ≤ 200

Turn it into a linear equation.

75x+ 40y =200

In order to go from one form to another, all you have to do is change the order of the given numbers. First you want to move the Ax to the opposite side of the equation, by either adding or subtracting it. At this point your equation will be set up By = -Ax + C. Then you want to divide the B from the By and the rest of the equation. Therefore you will have y = - Ax/B + C/B. This is the same thing as the slope-intercept form, just a few of the letters are different.

40y=-75x+200 first subtract 75x

y=−1.875×+5 then dived every varible (everything) by 40. and you have your Linear eqaution.

And your second question would be <em><u>A</u></em><em><u>.</u></em><em><u> </u></em><em><u>>The number of boxes must be a whole number.</u></em><em><u> </u></em>

Because you cannot split boxes in half or in any quarter in a real life scenario.

4 0
2 years ago
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