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PolarNik [594]
2 years ago
10

What is the difference between the equilibrium position and the equilibrium constant of a reaction? Which changes as a result of

a change in reactant concentration?
Chemistry
1 answer:
maria [59]2 years ago
3 0

If the concentrations of the substances present in the equilibrium are adjusted, the equilibrium constants remain unchanged. An equilibrium constant can only be altered by a change in temperature. If you adjust the concentration of something present in the mixture, the equilibrium position will change.

Equilibrium Constant vs. Equilibrium Position: The Difference

Equilibrium position is the point at which the forward reaction of the equilibrium is equal to the backward reaction, whereas equilibrium constant is the number that describes the connection between amounts of products and reactants of a reaction mixture at its equilibrium. The main distinction between equilibrium position and equilibrium constant is this.

To know more about Equilibrium Constant vs. Equilibrium Position

brainly.com/question/24175270

#SPJ4

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Give the name of one or more polysaccharides that matches each of the following descriptions:
adell [148]

Answer:

A Cellulose not digested by humans.

b. the storage form of carbohydrates in plants is starch

C amylose contains 1-4 glycosidic bond

D Glycogen and starch are highly branched polysaccharides.

Explanation:

8 0
2 years ago
When organizing your narrative, what are the 3 sections that make up a story (planning the specific order)
Sveta_85 [38]

Answer:

#1 Exposition

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3 0
3 years ago
Which is mostly likely to cause clouds to form in a previously clear sky?​
xxTIMURxx [149]

Answer:

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6 0
3 years ago
Read 2 more answers
What is the velocity of a electron whose wavelength is 100 pm?
Anni [7]

Answer:

v = 7.3 × 10⁶ m/s

Explanation:

Given data:

Velocity of electron = ?

Wavelength = 100 pm

Solution:

Formula:

λ = h/mv

λ = wavelength

h = planck's constant

m = mass

v = velocity

Now we will put the values in formula.

100 ×10⁻¹² m = 6.63 × 10⁻³⁴ j.s / 9.109 × 10⁻³¹ kg ×  v

v = 6.63 × 10⁻³⁴ kg.m²/s /  9.109 × 10⁻³¹ kg ×100 ×10⁻¹² m

v = 6.63 × 10⁻³⁴ m/s /910.9 × 10⁻⁴³

v = 0.0073  × 10⁹ m/s

v = 7.3 × 10⁶ m/s

5 0
3 years ago
What 2 pieces of equipment will you use to separate the salt from the water?
uysha [10]

Separate Salt and Water Using Distillation

If you want to collect the water, you can use distillation. This works because salt has a much higher boiling point than water. One way to separate salt and water at home is to boil the salt water in a pot with a lid.

hope this helps!!

8 0
2 years ago
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