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Gala2k [10]
3 years ago
10

What process uses analysis of the decay of atomic particles to determine exact age?

Chemistry
2 answers:
padilas [110]3 years ago
4 0

Answer:

Radioactive dating

Explanation:

Radioactive dating measures the ratio of C¹²(normal) and C¹⁴ (radioactive) in fossils to determine the exact age of the specimen. C¹⁴ is unstable and has a half life of 5730 years, so as the organism ages the amount of C¹⁴ diminishes but the amount of C¹² remains constant. The ratio of C¹⁴ to C¹² is used to analyze the decay of atomic particles to determine exact age.

Lesechka [4]3 years ago
3 0

Answer:

A

Explanation:

Because carbon-14 and uranium-235 are used in radioactive dating.

Hope it helped!

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55 L of a gas at 25oC has its temperature increased to 35oC. What is its new volume?
ladessa [460]

Answer:

Approximately 56.8 liters.

Assumption: this gas is an ideal gas, and this change in temperature is an isobaric process.

Explanation:

Assume that the gas here acts like an ideal gas. Assume that this process is isobaric (in other words, pressure on the gas stays the same.) By Charles's Law, the volume of an ideal gas is proportional to its absolute temperature when its pressure is constant. In other words

\displaystyle V_2 = V_1\cdot \frac{T_2}{T_1},

where

  • V_2 is the final volume,
  • V_1 is the initial volume,
  • T_2 is the final temperature in degrees Kelvins.
  • T_1 is the initial temperature in degrees Kelvins.

Convert the temperatures to degrees Kelvins:

T_1 = \rm 25^{\circ}C = (25 + 273.15)\; K = 298.15\; K.

T_2 = \rm 35^{\circ}C = (35 + 273.15)\; K = 308.15\; K.

Apply Charles's Law to find the new volume of this gas:

\displaystyle V_2 = V_1\cdot \frac{T_2}{T_1} = \rm 55\;L \times \frac{308.15\; K}{298.15\; K} = 56.8\; L.

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Cocaine is also an FDA-approved Schedule II . This means cocaine can be prescribed by a healthcare provider, but the process is strictly regulated.

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3 0
2 years ago
10.0 mL of a HF solution was titrated with a 0.120 N solution of KOH; 29.6 mL of
Ilia_Sergeevich [38]

Answer:

0.355 N of HF

Explanation:

The titration reaction of HF with KOH is:

HF + KOH → H₂O + KF

<em>Where 1 mole of HF reacts per mole of KOH</em>

<em />

Moles of KOH are:

0.0296L × (0.120 equivalents / L) = 3.552x10⁻³ equivalents of KOH = equivalents of HF.

As volume of the titrated solution was 10.0mL, normality of HF solution is:

3.552x10⁻³ equivalents of HF / 0.010L =<em> 0.355 N of HF</em>

3 0
3 years ago
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