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kirill [66]
1 year ago
5

a ship leaves port on a bearing of 44.0 degrees, and travels 11.4 mi. the ship turns east and travels 6.2 mi. How far is the shi

p from port and what is its bearing from.port
Mathematics
1 answer:
Rudik [331]1 year ago
7 0

Based on the information provided, \overrightarrow{r} = at a bearing angle of = 59.88° .

We are requested to calculate the overall displacement of the ship, both in magnitude and direction, once it departs the harbor under the stated parameters. First, let's define a bearing.

<h3>What is bearing in the context given above?</h3>

Angles are generally measured anticlockwise from the positive x-axis, whereas bearing angles are evaluated clockwise from the positive y-axis. A bearing is NOT a standard angle measuring tool.

Therefore, a bearing of 44.0° indicates that this is an angle 90.0° - 44.0° = 46°. This is the angle to be used in the calculations.

We're given that the first displacement is 11.4° at an angle of 46° (which was computed earlier).

Step 1  - Split the above into components

x1 = 11.4 Cos 46°

= 7.92m

y1 = 11.4Sin 46.0°

= 11.4 * 0.71933980033

= 8.2m

The second displacement is a simple 6.2mi due east, that is, the positive

x-direction. The components are thus:

Δx = x1 + x2

= 7.92 + 6.2

= 14.12mi

Δy = 1 + y2

= 8.2 + 0

= 8.2

r = √(x total)² + (y total)²

=√[(14.21)²+(8.2)²]

= √(201.9241 +67.24)

= √269.1641

= 16.4mi

The direction of the displacement vector is given by:

tan Ф = (Δy)/(Δx)

= arctan (8.2/14.12)

= arctan (0.5807365439)

= 30.12°

Recall that we were asked for the bearing angle. The bearing angle is what we get when we subtract 30.12° from 90°.

That is:
= 90 - 30.12

= 59.88°

Learn more about bearing angle:
brainly.com/question/22719608
#SPJ1

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Answer:

The longer piece will be 10 feet long.

Step-by-step explanation:

16 - 10 is 6

10 is 4 more than 6

therefore the longer piece will be 10 feet long

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<h3>What is a transformation of geometry?</h3>

A spatial transformation is each mapping of feature shapes to itself, and it maintains some spatial correlation between figures.

Reflection does not change the size and shape of the geometry.

The image of the figure under reflections in line m and then line t.

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2 years ago
1. The measure of side c is 150 feet and the
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Hi...

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7 0
3 years ago
Find the sum or difference. a. -121 2 + 41 2 b. -0.35 - (-0.25)
s344n2d4d5 [400]

Answer:

2

Step-by-step explanation:

The reason an infinite sum like 1 + 1/2 + 1/4 + · · · can have a definite value is that one is really looking at the sequence of numbers

1

1 + 1/2 = 3/2

1 + 1/2 + 1/4 = 7/4

1 + 1/2 + 1/4 + 1/8 = 15/8

etc.,

and this sequence of numbers (1, 3/2, 7/4, 15/8, . . . ) is converging to a limit. It is this limit which we call the "value" of the infinite sum.

How do we find this value?

If we assume it exists and just want to find what it is, let's call it S. Now

S = 1 + 1/2 + 1/4 + 1/8 + · · ·

so, if we multiply it by 1/2, we get

(1/2) S = 1/2 + 1/4 + 1/8 + 1/16 + · · ·

Now, if we subtract the second equation from the first, the 1/2, 1/4, 1/8, etc. all cancel, and we get S - (1/2)S = 1 which means S/2 = 1 and so S = 2.

This same technique can be used to find the sum of any "geometric series", that it, a series where each term is some number r times the previous term. If the first term is a, then the series is

S = a + a r + a r^2 + a r^3 + · · ·

so, multiplying both sides by r,

r S = a r + a r^2 + a r^3 + a r^4 + · · ·

and, subtracting the second equation from the first, you get S - r S = a which you can solve to get S = a/(1-r). Your example was the case a = 1, r = 1/2.

In using this technique, we have assumed that the infinite sum exists, then found the value. But we can also use it to tell whether the sum exists or not: if you look at the finite sum

S = a + a r + a r^2 + a r^3 + · · · + a r^n

then multiply by r to get

rS = a r + a r^2 + a r^3 + a r^4 + · · · + a r^(n+1)

and subtract the second from the first, the terms a r, a r^2, . . . , a r^n all cancel and you are left with S - r S = a - a r^(n+1), so

(IMAGE)

As long as |r| < 1, the term r^(n+1) will go to zero as n goes to infinity, so the finite sum S will approach a / (1-r) as n goes to infinity. Thus the value of the infinite sum is a / (1-r), and this also proves that the infinite sum exists, as long as |r| < 1.

In your example, the finite sums were

1 = 2 - 1/1

3/2 = 2 - 1/2

7/4 = 2 - 1/4

15/8 = 2 - 1/8

and so on; the nth finite sum is 2 - 1/2^n. This converges to 2 as n goes to infinity, so 2 is the value of the infinite sum.

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The given function is:

g(x)= \frac{10}{x}

The parents functions of g(x) will be:

f(x)= \frac{1}{x}

The domain of g(x) and its parent function is the same i.e. Set of all Real numbers except 0.

The range of g(x) and its parent function is the same i.e. set of all real numbers except 0. 

g(x) and its parent function only decrease. They do not increase over any interval. However, the interval in which they decrease is the same for both.

So, the correct answers are:
The domain of g(x) is the same as the domain of the parent function.
<span>The range is the same as the range of the parent function.
</span><span>The function g(x) decreases over the same x-values as the parent function.</span>
8 0
2 years ago
Read 2 more answers
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