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devlian [24]
3 years ago
11

What is the area of the triangle below?

Mathematics
1 answer:
Rudiy273 years ago
7 0

Answer:the answer is 68

Step-by-step explanation:

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Linda is planning to build a rectangular deck that is 12 feet longer than it is wide. Find its width if its area is 589 square f
BaLLatris [955]
Let the width be x, then the length is x + 12.
Area = length x width = x(x + 12) = 589
x^{2} +12x = 589
Solving the quadratic equation, we have that
x = 19 feet
i.e. the width is 19 feet.
6 0
4 years ago
Could anyone help with this, im terrible at geometry haha
Natalija [7]

Answer:

m<ACD = 90

m<CDB = 126

m<EDB = 54

m<CDE = 180

Step-by-step explanation:

Well you have the right girl! *In honors geometry you can trust me!

Ok first thing...We already know

B = 54

A = 90  

D = 54 (It's the Alternate interior angle of B)

C = 90

m<ACD = 90 (C = 90)

m<CDB = 126 (D = 54 ------> 180-54= 126)

m<EDB = 54 (Alternate Interior angle of B)

m<CDE = 180 (It is a straight line)

Hope this helps ya!!

7 0
3 years ago
Find the measure of each angle:
Mrac [35]
Supplementary angles sum up to 180 degrees.

2x - 4 + 2x + 4 = 180
4x = 180
x = 45

Therefore,
m<9 = 2(45) - 4 = 90 - 4 = 86 degrees
m<10 = 2x + 4 = 90 + 4 = 94 degrees.
4 0
3 years ago
Read 2 more answers
$8.50 yoga mat; 75% markup
Alenkinab [10]
The answer is:
14.875
Hope this helps
3 0
3 years ago
Consider the circle of radius 5 centered at (0,0), how do you find an equation of the line tangent to the circle at the point (3
Flauer [41]

\text{We know that the tangent at any point on a circle is perpendicular}\\&#10;\text{to the radius at that point.}\\&#10;\\&#10;\text{so first we find the equation of the line joining (0,0) and (3,4)}\\&#10;\text{and then using the slope, we find the line perperndicular to it at (3,4)}\\&#10;\\&#10;\text{the equation of the line passing through (0,0) and (3,4) is}\\&#10;\\&#10;y-0=\frac{4-0}{3-0}(x-0)

\Rightarrow y=\frac{4}{3}x\\&#10;\\&#10;\text{so the slope of radius is }m=\frac{4}{3}.\\&#10;\\&#10;\text{we know that the product of the perpendicular lines is }-1. \\&#10;\\&#10;\text{so the slope of the perpendicular line would be}=-\frac{1}{4/3}=-\frac{3}{4}\\&#10;\\&#10;\text{So the equation of the tangent line has slope }-\frac{3}{4} \text{ and}\\&#10;\text{passing through (3,4). so equation of tangent line is}

y-4=-\frac{3}{4}(x-3)\\&#10;\\&#10;\Rightarrow y-4=-\frac{3}{4}x+\frac{9}{4}\\&#10;\\&#10;\Rightarrow y=-\frac{3}{4}x+\frac{9}{4}+4\\&#10;\\&#10;\Rightarrow y=-\frac{3}{4}x+\frac{9+16}{4}\\&#10;\\&#10;\text{so the equation of tangent line is:} y=-\frac{3}{4}x+\frac{25}{4}

5 0
4 years ago
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