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2 years ago

PLEASE HELP ASAP ITS GEOMETRY

Mathematics

1 answer:

Gwar [14]2 years ago

4 0

The missing options that makes up the distance formula between two coordinates are; (x₂ - x₁)² and d²

How to find the distance between two coordinates?

The formula for distance between two coordinates is;

d = √[(y₂ - y₁)² + (x₂ - x₁)²]

where;

(x₁, y₁) is the coordinate of the first point

(x₂, y₂) is the coordinate of the second point

Now, this distance formula can also be rewritten when we square both sides to get;

(y₂ - y₁)² + (x₂ - x₁)² = d²

Thus, the missing options that makes up the distance formula between two coordinates are; (x₂ - x₁)² and d²

Read more about distance between two coordinates at; brainly.com/question/7243416

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What is net worth why do people say he or she is worth that?

Deffense [45]

Answer:

The net worth of a person is the difference between a person's assets (non-financial and financial) that he/she owns and the debt that person owes.

Value of Assets - Debt and liabilities = Net Worth

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3 years ago

Mercy marks up all goods she sells by 30%.What is the mark up of a hat that cost her $42?

Delvig [45]

Answer:

$12.60

Step-by-step explanation:

42/30%=42/0.3=$12.60

Brainleist plz

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3 0

3 years ago

Find the LCM of 6 and 15. A) 6 B) 15 C) 30 D) 90

erastovalidia [21]

Answer:

Step-by-step explanation:

the answer is 30 because if you count by 6 it would go 6,12,18,24,30,36,42 and if you go by 15 it would be 15,30,45,60,75,90..... and the only number that you see twice is 30 so the answer would be 30. Hope this helped...

3 0

3 years ago

Read 2 more answers

Solve the following equation by completing the square. 3x^2-3x-5=13

mr Goodwill [35]

we'll start off by grouping some

$\bf 3x^2-3x-5=13\implies (3x^2-3x)-5=13\implies 3(x^2-x)-5=13 \\\\\\ 3(x^2-x)=18\implies (x^2-x)=\cfrac{18}{3}\implies (x^2-x)=6\implies (x^2-x+~?^2)=6$

so we have a missing guy at the end in order to get the a perfect square trinomial from that group, hmmm, what is it anyway?

well, let's recall that a perfect square trinomial is

$\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2$

so we know that the middle term in the trinomial, is really 2 times the other two without the exponent, well, in our case, the middle term is just "x", well is really -x, but we'll add the minus later, we only use the positive coefficient and variable, so we'll use "x" to find the last term.

$\bf \stackrel{\textit{middle term}}{2(x)(?)}=\stackrel{\textit{middle term}}{x}\implies ?=\cfrac{x}{2x}\implies ?=\cfrac{1}{2}$

so, there's our fellow, however, let's recall that all we're doing is borrowing from our very good friend Mr Zero, 0, so if we add (1/2)², we also have to subtract (1/2)²

$\bf \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2-\left[ \cfrac{1}{2} \right]^2 \right)=6\implies \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2 \right)-\left[ \cfrac{1}{2} \right]^2=6 \\\\\\ \left(x-\cfrac{1}{2} \right)^2=6+\cfrac{1}{4}\implies \left(x-\cfrac{1}{2} \right)^2=\cfrac{25}{4}\implies x-\cfrac{1}{2}=\sqrt{\cfrac{25}{4}} \\\\\\ x-\cfrac{1}{2}=\cfrac{\sqrt{25}}{\sqrt{4}}\implies x-\cfrac{1}{2}=\cfrac{5}{2}\implies x=\cfrac{5}{2}+\cfrac{1}{2}\implies x=\cfrac{6}{2}\implies \boxed{x=3}$

6 0

3 years ago

X = ? Degrees Y= ? Degrees

Dmitry_Shevchenko [17]

Answer:

X = i don't know

Y = 50°

Step-by-step explanation:

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8 0

2 years ago