Question

Please solve with explanation will give BRAINLIEST and Bonus Points

Answer 1

Let d = # of dimes

Let q = # of quarters

equation #1: number of coins

    d + q = 1234

equation #2: value of coins

    0.10d + 0.25q = 290.05

Solve #1 for d:

    d=1234-q

Sub #1 into #2 and solve for q:

    0.10d + 0.25q = 290.05

    0.10(1234-q) + 0.25q = 290.05

    123.4 - 0.10q + 0.25q = 290.05

    0.15q =  166.65

    q = 1111

Now go back to d=1234-q and sub in 1111 for q to find d:

    d = 1234 - 1111

    d = 123

1111 quarters and 123 dimes.