Indicate whether each percent of change is an increase or decrease, then find the percent of change. Round to the nearest tenth
1 answer:
You might be interested in
Answer:
We conclude that there is a difference in seat belt use.
Step-by-step explanation:
We are given that of 1,000 drivers 16-24 years old, 79% said they buckle up, whereas 924 of 1,100 drivers 25-69 years old said they did.
<u><em>Let </em></u><u><em> = population proportion of drivers 16-24 years old who buckle up .</em></u>
<u><em /></u><u><em> = population proportion of drivers 25-69 years old who buckle up .</em></u>
So, Null Hypothesis, :
= 0 {means that there is no significant difference in seat belt use}
Alternate Hypothesis, :
0 {means that there is a difference in seat belt use}
The test statistics that would be used here <u>Two-sample z proportion statistics;</u>
T.S. = ~ N(0,1)
where, = sample proportion of drivers 16-24 years old who buckle up = 79%
= sample proportion of drivers 25-69 years old who buckle up =
= 84%
= sample of 16-24 years old drivers = 1000
= sample of 25-69 years old drivers = 1100
So, <u><em>test statistics</em></u> =
= -2.946
The value of z test statistics is -2.946.
Since, in the question we are not given with the level of significance so we assume it to be 5%. <u><em>Now, at 0.05 significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.</em></u><em> </em>
<em>Since our test statistics doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>
Therefore, we conclude that there is a difference in seat belt use.