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stich3 [128]
3 years ago
13

Y=-1/2x+4 What is the slope of a line parallel to this line?

Mathematics
2 answers:
Pani-rosa [81]3 years ago
7 0

The parallel slope would be -1/2. A parallel line that has the same slope as the original line.

olga_2 [115]3 years ago
3 0

Answer:

-1/2

Step-by-step explanation:

Since it’s the slope of a parallel line the slope is going to be equal to the line. If it was the slope of a perpendicular line you would find the opposite reciprocals of -1/2.

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Write an equation in standard form of the hyperbola described.
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Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.

\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill

\begin{cases} h=0\\ k=0\\ a=2\\ c=4 \end{cases}\implies \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{b^2} \\\\\\ c^2=a^2+b^2\implies 4^2=2^2+b^2\implies 16=4+b^2\implies \underline{12=b^2} \\\\\\ \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{12}\implies \boxed{\cfrac{x^2}{4}-\cfrac{y^2}{12}}

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2 years ago
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Hi! I hope this is correct please inform me if this is incorrect :)

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ANY others I did not include in a = 1 :)

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Step-by-step explanation:

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