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3 years ago

I need a quick good conclusion thank you

Mathematics

1 answer:

Debora [2.8K]3 years ago

8 0

You'll notice that 36's prime factors had 2 even, and none other had an even number of even prime factors. Therefore, if you have an even number of even prime factors, your square root will be rational given the data

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A particular fruit's weights are normally distributed, with a mean of 406 grams and a standard deviation of 27 grams.The heavies

Tom [10]

Given

mean of 406 grams and a standard deviation of 27 grams.

Find

The heaviest 14% of fruits weigh more than how many grams?

Explanation

given

mean = 406 gms

standard deviation = 27 gms

using standard normal table ,

$\begin{gathered} P(Z>z)=14\% \\ 1-P(Zso , [tex]\begin{gathered} x=z\times\sigma+\mu \\ x=1.08\times27+406 \\ x=435.16 \end{gathered}$

Final Answer

Therefore , The heaviest 14% of fruits weigh more than 435.16 gms

8 0

1 year ago

Write y=-3x^2+12x-21 in vertex form

riadik2000 [5.3K]

Complete the square:
y = 3x^2 - 12x + 4 
y = 3(x^2 - 4x) + 4 
y = 3(x^2 - 4x + 4 - 4) + 4 
y = 3(x^2 - 4x + 4) - 12 + 4 
y = 3(x - 2)^2 - 8

5 0

3 years ago

Read 2 more answers

The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t

shtirl [24]

Answer:

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

Step-by-step explanation:

As the given Augmented matrix is

$\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 1 :

$r_{1}$ ↔ $r_{1} - r_{2}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 2 :

$r_{3}$ ↔ $r_{3} - 8r_{1}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]$

Step 3 :

$r_{2}$ ↔ $\frac{r_{2}}{7}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]$

Step 4 :

$r_{1}$ ↔ $r_{1} + 14r_{2}$ , $r_{3}$ ↔ $r_{3} - 124r_{2}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]$

Step 5 :

$r_{3}$ ↔ $\frac{r_{3}. 7}{254}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]$

Step 6 :

$r_{1}$ ↔ $r_{1} - 4r_{3}$ , $r_{2}$ ↔ $r_{2} + \frac{1}{7} r_{3}$

$\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]$

∴ we get

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

6 0

3 years ago

Please help will give brainliest

valkas [14]

Answer:The second answer there are 3 kids and one adult and the ratio would be 3:1 .

Step-by-step explanation:

4 0

3 years ago

What is (6 + 3e)4 - 5e and 3(x - 5) + 7(x + 2) ?

Dafna11 [192]

idk lol use photomath

6 0

3 years ago