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ladessa [460]
2 years ago
9

In which set(s) of numbers would you find the number

Mathematics
1 answer:
balu736 [363]2 years ago
3 0

Answer:

A, C

Step-by-step explanation:

Rational: Yes, because it is a terminating decimal, and is thus rational.

Real: Yes, all rational numbers are real.

Irrational: No, because it is rational.

Integer: No, because its fractional part is nonzero.

Whole: No, because it is not an integer.

Natural: No, because it is not an integer.

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SIZIF [17.4K]

Answer:

Well it varies for how many lines you put on the graph, if you use desmos the answer comes out as 40 units; 25 units to the right of (-4,1) and 20 down

Step-by-step explanation:

5 0
3 years ago
I need help with this question please !!
RSB [31]

Answer:

100, because 180 - 50 - 90 = 40

The vertical angles theorem is applied, so now angle DCE is 40

And since CE = ED, its isosceles triangle, so base angles are equal, so 40 and 40.

180 - 80 = 100 = Angle E.

4 0
3 years ago
Find (a) the amplitude, (b) the wavelength, (c) the period, and (d) the speed of a wave whose displacement is given by y= 1.5 co
leonid [27]

Answer with Step-by-step explanation:

We are given that displacement of wave

y=1.5cos(0.68x+37t)

Where y in cm  and t in sec.

a.Compare it with

y=Acos(kx+\omega t)

Amplitude of wave=A

We get A=1.5

Amplitude=A=1.5  cm

b.k=0.68

\frac{2\pi}{\lambda}=0.68

\lambda=\frac{2\times 3.14}{0.68}=9.2 cm

Using \pi=3.14

Wavelength of the wave=9.2 cm

c.Period=\frac{2\pi}{T}=\omega

\frac{2\pi}{T}=37

T=\frac{2\times 3.14}{37}=0.17 s

The period of the wave=0.17 s

Speed of the wave=\nu \lambda=\frac{\lambda}{T}=\frac{9.2}{0.17}

Speed of the wave=54.1 cm/s

8 0
3 years ago
The primary deliverables from requirements determination include: A. sets of forms, reports, and job descriptions B. transcripts
Ganezh [65]

Answer:

D. All of these

Step-by-step explanation:

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3 0
3 years ago
What number should be added to the expression x2 + 4x to change it into a perfect square trinomial?
Elden [556K]
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3 0
3 years ago
Read 2 more answers
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