Answer:
After the extended period of time, Pete would have typed 6400 words.
Step-by-step explanation:
Given the data in the question;
In the same time;
number typed word of Pete = 80
type word of Ralph = 50
After a period time;
number of typed word of Pete = ?
number of typed word of Ralph = 4000
so, let x represent the number of typed word by Pete after an extended period.
so
80 words = 50 words
x words = 4000 words
we cross multiply
x × 50 = 4000 × 80
x = ( 4000 × 80 ) / 50
x = 320000 / 80
x = 6400
Therefore, After the extended period of time, Pete would have typed 6400 words.
You can write it in the form a^2 - b^2 where a = 5x and b = p
(5x)^2 - p^2
And then use the Difference of Squares a^2 - b^2 = (a + b)(a - b)
Answer is (5x + p)(5x - p)
It is 13 I think hopefully this the right answer hope I helped you
Check the picture below.
now, if AC is that much, recall, BD is the midsegment, thus AB = BC, so AB is just one of the equal halves of AC, so, AB is AC/2.
Whether dividing constant terms or polynomials, we always have definitive terms when it comes to division. Suppose we say, 10x divided by 2. The dividend is the 10x and the divisor is the 2. In other words, the dividend is the number to be divided by the divisor, to obtain the answer called the quotient.
When dividing polynomials, your main goal is to be able to divide the dividend evenly into the <em>divisor</em>. For example, we divide x²+2x+1 by x+1. The first thing you're going to focus is, what term will completely divide the first term of the polynomial? That would be x. Why? Because when you multiply x with x+1, the product is x²+x. When you subtract this from the polynomial, the x² will cancel out. All you have to do is subtract x from 2x, yielding x. Then, you carry down the last term of the equation: +1. You do the steps again. The term that will completely divide x+1 by x+1 is 1. When you subtract the two, you will come up with zero. That means there is no remainder. The polynomial is divisible by the divisor.
x + 1
------------------------------------
x+1| x²+2x+1
- x²+x
----------------------
x +1
- x +
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0
