<BAC = <DEC = 30°
<BCA = <DCE = 70°
<CDE (or m<D) = 180° - <DEC - <DCE
<CDE = 180° - 30° - 70°
<CDE = 80°
The number that belongs in the green box is 80
Answer:
Let's find the area of 1 triangle (this may not be the formula but I'm doing it in a more easier way).
20(base) x 10.5(height) = 210
210 divided by 2 ( x 1/2) = 105
Since there are 4 sides we must multiply the area of 1 triangle four times! Since there are 4 sides of triangles.
105 x 4 = 420
Oh and I almost forgot! We need to find the area of the square below!
20 x 20 = 400!
Now we add both areas of all the triangles and the area of the bottom square:
420 + 400 = 820 in2 is your answer. (we use the unit 2 since we are finding areas and adding them up)
Formula of a triangle:
BH x 1/2
B(base) x H(height) x 1/2 (basically just dividing by 2)
Answer:
90 = | x - 122 |
Step-by-step explanation:
Given;
maximum temperature, 212 °F
minimum temperature, 32 °F
First, determine the difference of both values;
212 - 32 = 180
Divide this value by 2
180/2 = 90
90 = | x - 212 + 90|
90 = | x - 122 |
where;
x is the temperature of water
Thus, the absolute value equation that represents the minimum and maximum temperature of liquid water is 90 = | x - 122 |
The answer is 19,448 different
groups, using the formula from permutation and combinations C (n, r) = (n!) /
(r! (n-r)!) which calculates the number of times where r objects can be chosen
from n object.
So,
C (17,7) = (17!) / (7! *(17-7)!)
C (17,7) = (17!) / (7! *10!)
C (17,7) =
(17*16*15*14*13*12*11*10!) / (7! *10!) then eliminate 10!
C (17,7) = (17*16*15*14*13*12*11)
/ (7*6*5*4*3*2*1) = (98017920)(5040)
C (17,7) = 19,448 different
groups
Answer:
u=−x2−x+1
Step-by-step explanation:
Let's solve for u.
2x−u−1x^2−3x+3=2
Step 1: Add x^2 to both sides.
−x2−u−x+3+x2=2+x2
−u−x+3=x2+2
Step 2: Add x to both sides.
−u−x+3+x=x2+2+x
−u+3=x2+x+2
Step 3: Add -3 to both sides.
−u+3+−3=x2+x+2+−3
−u=x2+x−1
Step 4: Divide both sides by -1.
−u/−1=x2+x−1
−1/u=−x2−x+1
Answer:
u=−x2−x+1
