The answer to the question is the second option.
Answer:
41.5?
Step-by-step explanation:
is that it to the question or is there more?!?!
<span>The ordinate is three more than twice the abscissa
</span>Ordnate: y; Abscissa: x
y=3+2x
x=-1→y=3+2(-1)=3-2→y=1→(x,y)=(-1,1)
x=0→y=3+2(0)=3+0→y=3→(x,y)=(0,3)
x=-1/3→y=3+2(-1/3)=3-2/3=(3*3-2)/3=(9-2)/3→y=7/3→(x,y)=(-1/3,7/3)
Answer: Option <span>A) {(-1,1),(0,3),(-1/3,7/3)}</span>
This is what I could find.
Draw a 53° angle in standard position together with a unit circle<span>. Use the triangle below to </span>find<span> the x- any y-</span>coordinates<span> of the </span>point<span> of intersection of the terminal side and the </span>circle<span>. Compute and . Confirm that they are equal to and .</span>
