Triangles PQR and XYZ are similar. What is the length of XZ?

Solve for b2 in A = 1/2 h ( b1 + b2 ), if A = 16, h = 4, and b1 = 3.

Katarina [22]

Hello from MrBillDoesMath!

Answer:

b2 = 5

Discussion:

A = 1/2 h (b1 + b2) .

Substituting A = 16, h = 4, and b1=3 in the above formula gives:

16 = (1/2) (4)( 3 + b2) => (as (1/2)4 = 2) )

16 = 2 ( 3 + b2) => (divide both sides by 2)

8 = (3 + b2) => (subtract 3 from both sides)

8-3 = b2 =>

5 = b2

Check Area formula:

Does A = 16 = (1/2)(4)(3+5) ?

Does 16 = (1/2) (4)(8) ?

Does 16 = (1/2)(32) ? Yes it does so our calculation for b2 is correct

Thank you,

MrB

7 0

3 years ago

Which angles are adjacent to 8 ? select all that apply

Alinara [238K]

Answer:

I think 5 and 7 I got that question

3 0

3 years ago

Read 2 more answers

que cantidad de ingereses genera un prestamo de 10000 dolares que se contrato el 1 de agosto de 2017 para reembolsarse el 1 de a

egoroff_w [7]

Answer:

que cantidad de ingereses genera un prestamo de 10000 dolares que se contrato el 1 de agosto de 2017 para reembolsarse el 1 de agosto de 2020, con interes simple del 10 % anua

6 0

3 years ago

Assume that females have pulse rates that are normally distributed with a mean of μ=73.0 beats per minute and a standard deviati

Gennadij [26K]

Answer:

a. the probability that her pulse rate is less than 76 beats per minute is 0.5948

b. If 25 adult females are randomly selected, the probability that they have pulse rates with a mean less than 76 beats per minute is 0.8849

c. D. Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

Step-by-step explanation:

Given that:

Mean μ =73.0

Standard deviation σ =12.5

a. If 1 adult female is randomly selected, find the probability that her pulse rate is less than 76 beats per minute.

Let X represent the random variable that is normally distributed with a mean of 73.0 beats per minute and a standard deviation of 12.5 beats per minute.

Then : X $\sim$ N ( μ = 73.0 , σ = 12.5)

The probability that her pulse rate is less than 76 beats per minute can be computed as:

$P(X < 76) = P(\dfrac{X-\mu}{\sigma}< \dfrac{X-\mu}{\sigma})$

$P(X < 76) = P(\dfrac{76-\mu}{\sigma}< \dfrac{76-73}{12.5})$

$P(X < 76) = P(Z< \dfrac{3}{12.5})$

$P(X < 76) = P(Z< 0.24)$

From the standard normal distribution tables,

$P(X < 76) = 0.5948$

Therefore , the probability that her pulse rate is less than 76 beats per minute is 0.5948

b. If 25 adult females are randomly selected, find the probability that they have pulse rates with a mean less than 76 beats per minute.

now; we have a sample size n = 25

The probability can now be calculated as follows:

$P(\overline X < 76) = P(\dfrac{\overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{ \overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}})$

$P( \overline X < 76) = P(\dfrac{76-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{76-73}{\dfrac{12.5}{\sqrt{25}}})$

$P( \overline X < 76) = P(Z< \dfrac{3}{\dfrac{12.5}{5}})$

$P( \overline X < 76) = P(Z< 1.2)$

From the standard normal distribution tables,

$P(\overline X < 76) = 0.8849$

c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?

In order to determine the probability in part (b); the normal distribution is perfect to be used here even when the sample size does not exceed 30.

Therefore option D is correct.

Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

5 0

3 years ago

Find X in the triangle. Round answer to the nearest TENTH of a degree (GIVING BRAINLEST TO BEST ANSWER :D )

Sergio [31]

Answer:

x = 59,53445508

Tan(x) = 34/20

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers