Triangles PQR and XYZ are similar. What is the length of XZ?

Given the following triangle, if b = 9 and B = 15°, find a. 0.27 2.41 33.59

SVEN [57.7K]

SOH,CAH, TOA so it would be TANGENT since it would be Opposite over Adjacent. Tan(15) = 9/a put Tan(15) onto your calculator it would be .267949 round that to .27 = 9/a cross multiply
a = 33.588. C is the correct answer.

7 0

3 years ago

Read 2 more answers

VEEL

Andre45 [30]

Answer:

$a_n=-3(3)^{n-1}$ ; {-3,-9, -27,- 81, -243, ...}

$a_n=-3(-3)^{n-1}$ ; {-3, 9,-27, 81, -243, ...}

$a_n=3(\frac{1}{2})^{n-1}$ ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

$a_n=243(\frac{1}{3})^{n-1}$ ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

$a_n=-3(3)^{n-1}$

At n=1,

$a_1=-3(3)^{1-1}=-3$

At n=2,

$a_2=-3(3)^{2-1}=-9$

At n=3,

$a_3=-3(3)^{3-1}=-27$

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

$a_n=-3(-3)^{n-1}$

At n=1,

$a_1=-3(-3)^{1-1}=-3$

At n=2,

$a_2=-3(-3)^{2-1}=9$

At n=3,

$a_3=-3(-3)^{3-1}=-27$

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

$a_n=3(\frac{1}{2})^{n-1}$

At n=1,

$a_1=3(\frac{1}{2})^{1-1}=3$

At n=2,

$a_2=3(\frac{1}{2})^{2-1}=1.5$

At n=3,

$a_3=3(\frac{1}{2})^{3-1}=0.75$

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

$a_n=243(\frac{1}{3})^{n-1}$

At n=1,

$a_1=243(\frac{1}{3})^{1-1}=243$

At n=2,

$a_2=243(\frac{1}{3})^{2-1}=81$

At n=3,

$a_3=243(\frac{1}{3})^{3-1}=27$

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0

3 years ago

What is the quotation -3/8 divided by -1/4

Bumek [7]

Answer:

3/2

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

An employer may conduct an aptitude test to check for what

AysviL [449]

Your ability to solve problems.
Hope this helps!

7 0

3 years ago

Read 2 more answers

Find the Lateral area for the regular pyramid. (Keep it as a Square Root)

Shtirlitz [24]

1. You must apply the following formula:

LA=1/2 ×(Perimeter of the base)(Slant length)

2. The slant length is (By the Pythagorean Theorem):

a^2=b^2+c^2

a= b^2+c^2

a=√(1^2+3^2)

a=√10

3. The perimeter of the base is:

P=2+2+2+2

P=8

4. Then, you have:

LA=1/2 ×(Perimeter of the base)(Slant Length)

LA=1/2 ×(8)(√10)

LA=(8√10)/2

LA=4√10

3 0

2 years ago