In this question , we have to find the value of tan 30 and we need to write the answer in simplified form .

Substituting the values of sin (30) and cos(30, we will get

Multiplying both numerator and denominator by 2, we will get

TO simplify it, we need to multiply both numerator and denominator by square root 3.

The force the same object will exert if it accelerates at a rate of 7 m/s² is 35N
From the question,
We are to determine the force the object will exert.
From the information,
Newton’s Second Law of Motion states that the acceleration of an object is directly proportional to the force exerted on the object
Let acceleration be a
and
Force be F
Then we can write that,
F ∝ a
Then,
Introducing the constant, mass, m
We get
F = ma
Now, we will determine the mass of the object
F = 15 N
a = 3 m/s²
Putting the parameters into the formula, we get
15 = m × 3
∴ m = 15 ÷ 3
m = 5 kg
The mass of the object is 5 kg.
Now, to determine the force the same object will exert if it accelerates at a rate of 7 m/s²
That is,
a = 7 m/s²
and
m = 5 kg
Putting the parameters into the formula, we get
F = 5 × 7
F = 35 N
Hence, the force the same object will exert if it accelerates at a rate of 7 m/s² is 35N
Learn more here: brainly.com/question/13590154
Answer: B
Step-by-step explanation: if you divide 27/30 by 3 you get 9/10
Answers:
- Choice B) y = (1/4)x
- The unit rate is <u> 3.89 </u> dollars per pound. It costs <u> 23.34 </u> dollars for a turkey that weighs 6 pounds.
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Explanations:
- Direct proportional equations are always in the form y = kx, where k is some constant. In the case of choice B, we have k = 1/4. Visually, direct proportion equations are always straight lines and go through the origin.
- Divide $34.99 over 9 to get 34.99/9 = 3.88777 approximately. This rounds to 3.89, so it costs $3.89 per pound. That's the unit rate. Multiply this by 6 to get 6*3.89 = 23.34 which is the cost of the 6 pound turkey.
Answer
An equilateral.
Step-by-step explanation:
The degrees are the same and so 60=60=60. The triangle is a equilateral.