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umka2103 [35]
2 years ago
8

Suppose c>d. explain why the following inequalities are true:

Mathematics
1 answer:
Aneli [31]2 years ago
7 0

Answer: Optional

Step-by-step explanation:

Since c is greater than d, 2c would be greater than 2d, because when it’s like this 2c

It sometimes means multiply.

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I<br> 1<br> 8 in<br> Find h.<br> 13 in<br> = √[?] in.
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as the following pic you can see the answer.

#diameter is 8 so radius is 4

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Q7 Q22.) How far is the ball from the center of the​ green?
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See the attached picture:

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6) Find the measure of ∠G.
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Answer:

m<G = 71

Step-by-step explanation:

Find x first

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Combine like terms:

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      - 50    - 50

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Brian irons 2/9 of his shirt in 3 3/5 minutes. At this rate, how much of his shirt does he iron each minute?
vodka [1.7K]

The speed for which Brian iron the shirts is given by:

R = \frac{\frac{2}{9}}{3\frac{3}{5}}

Rewriting we have:

R = \frac{\frac{2}{9}}{\frac{18}{5}}

R = \frac{10}{162}

Then, for each minute, we have the amount of ironed shirt is:

(\frac{10}{162})(1) = \frac{10}{162}

Answer:

At this rate, Brian plans 10/162 of his shirt.

8 0
3 years ago
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Mr. Brady is using a coordinate plane to design a treasure hunt for his students. The hunt begins at the flagpole. The first clu
dmitriy555 [2]

Answer:

The figure is attached and the total distance is 1031 feet.

Step-by-step explanation:

The graph is indicated in the attached figure.

For calculation of distance consider following

Point Flagpole is (0,0)

Point Clue1 is (0,5)

Point Clue2 is (6,0)

Point Clue3 is (0,-5)

So the distance is calculated as follows

d_{T}=[d_{FP\ to\ Clue1}+d_{Clue1\ to\ Clue2}+d_{Clue2\ to\ Clue3}]*distance\ per\ unit\\d_{T}=[\sqrt{(Clue1_x-FP_x)^2+(Clue1_y-FP_y)^2}+\sqrt{(Clue2_x-Clue1_x)^2+(Clue2_y-Clue1_y)^2}+\sqrt{(Clue3_x-Clue2_x)^2+(Clue3_y-Clue2_y)^2}]**distance\ per\ unit\\Substituting the values

d_{T}=[\sqrt{(0-0)^2+(5-0)^2}+\sqrt{(6-0)^2+(0-5)^2}+\sqrt{(0-6)^2+(-5-0)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{(0)^2+(5)^2}+\sqrt{(6)^2+(-5)^2}+\sqrt{(-6)^2+(-5)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{0+25}+\sqrt{36+25}+\sqrt{36+25}]*50 \text{ feet}\\d_{T}=[\sqrt{25}+\sqrt{61}+\sqrt{61}]*50 \text{ feet}\\d_{T}=[5+7.81+7.81]*50 \text{ feet}\\d_{T}=[20.62]*50 \text{ feet}\\d_{T}=1031 \text{ feet}\\

So the total distance travelled is 1031 feet.

4 0
3 years ago
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