Question

sam is eating a hamburger. He at 20% of the hamburger with his first bite, 20% of what is left in his second bite, and so on, eating 20% of what remains with each bite. How much did the hamburger weigh, if there was originally 160g of it remaining after the second bite

Answer 1

The hamburger will weigh 250 g, if there was originally 160g of it remaining after the second bite given that 20% of the hamburger with his first bite, 20% of what is left in his second bite, and so on, eating 20% of what remains with each bite. This can be obtained by assuming the total weight as x and multiplying the percentages.

How much did the hamburger weigh?

Let the total weight of the hamburger be x.

• First it is given that Sam ate 20% of the hamburger.

The first bite will be,

20% of the hamburger = 20% × x

20% of the hamburger = 20/100 × x

20% of the hamburger = 20x/100

⇒ first bite = 20x/100

Therefore the remaining hamburger will be,

remaining hamburger = x - 20x/100

remaining hamburger = (100x - 20x)/100

⇒ remaining hamburger after first bite = 80x/100

• Next it is given that Sam ate 20% of the remaining hamburger.

The second bite will be,

20% of the remaining hamburger = 20% × 80x/100

20% of the remaining hamburger = 20/100 × 80x/100

20% of the remaining hamburger = 16x/100

⇒ second bite = 16x/100

Therefore the remaining hamburger will be,

remaining hamburger = 80x/100 - 16x/100

remaining hamburger after second bite = 64x/100

• It is given that there was originally 160g of it remaining after the second bite.

Then, 64x/100 = 160

x = 160 × 100/64

x = 250 g

Hence the hamburger will weigh 250 g, if there was originally 160g of it remaining after the second bite given that 20% of the hamburger with his first bite, 20% of what is left in his second bite, and so on, eating 20% of what remains with each bite.

Learn more about percentages here:

brainly.com/question/25395

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