The hamburger will weigh 250 g, if there was originally 160g of it remaining after the second bite given that 20% of the hamburger with his first bite, 20% of what is left in his second bite, and so on, eating 20% of what remains with each bite. This can be obtained by assuming the total weight as x and multiplying the percentages.
<h3>How much did the hamburger weigh?</h3>
Let the total weight of the hamburger be x.
- First it is given that Sam ate 20% of the hamburger.
The first bite will be,
20% of the hamburger = 20% × x
20% of the hamburger = 20/100 × x
20% of the hamburger = 20x/100
⇒ first bite = 20x/100
Therefore the remaining hamburger will be,
remaining hamburger = x - 20x/100
remaining hamburger = (100x - 20x)/100
⇒ remaining hamburger after first bite = 80x/100
- Next it is given that Sam ate 20% of the remaining hamburger.
The second bite will be,
20% of the remaining hamburger = 20% × 80x/100
20% of the remaining hamburger = 20/100 × 80x/100
20% of the remaining hamburger = 16x/100
⇒ second bite = 16x/100
Therefore the remaining hamburger will be,
remaining hamburger = 80x/100 - 16x/100
remaining hamburger after second bite = 64x/100
- It is given that there was originally 160g of it remaining after the second bite.
Then, 64x/100 = 160
x = 160 × 100/64
x = 250 g
Hence the hamburger will weigh 250 g, if there was originally 160g of it remaining after the second bite given that 20% of the hamburger with his first bite, 20% of what is left in his second bite, and so on, eating 20% of what remains with each bite.
Learn more about percentages here:
brainly.com/question/25395
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