Area of pool edge = Area of big rectangle - Area of the pool
Area of pool edge = Area of the pool = 40 × 60 = 2400 ft²
2400 = Area of big rectangle - 2400
Area of big rectangle = 2400 + 2400
Area of big rectangle = 4800
Length × width = 4800
From the diagram, we need the length to be [x + x] more than the length of the pool, where x is the distance from the pool edge to the patio edge.
We also need the width of the big rectangle to be [[x + x] more than the width of the pool.
Length = 60 + 2x
Width = 40 + 2x
Length × Width = [60+2x] × [40+2x]
4800 = 2400 + 120x + 80x + 4x²
0 = 4x² + 200x - 2400
0 = 4[x² + 50x - 600]
0 = x² + 50x - 600
0 = [x - 60] [x + 10]
x - 60 = 0 OR x + 10 = 0
x = 60 OR x = -10
We can only use the positive value of x since the context is length
Hence, x = 60
<span>•<span>If
the raw score is transformed into a z-score, however, the value of the z-score
tells exactly where the score is located relative to all the other scores in
the distribution. </span></span>
Answer: x = 108
Step-by-step explanation: In this problem, we're given a diagram and
we're asked to find the value of x that would make m ll n.
We can see that the angles that are marked in the diagram
are same-side interior angles since they lie on the same side
of the transversal and they lie on the interior of lines m and n.
Therefore, in order for line m to be parallel to line n,
these angles must be supplementary.
In other words, they must add to 180 degrees.
So we can setup the equation x + 72 = 180.
Subtracting 72 from both sides gives us x = 108.
So the value of x that would make line m ll n is 108.
Answer:
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Step-by-step explanation:
Answer:someone answer the question already
Step-by-step explanation: