Let G be some point on the diagonal line away from point E.
Angle DEG represents angle 1.
We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.
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Extra side notes:
If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.
If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.
Answer:true
Step-by-step explanation:
Answer:
C. $12.60
Step-by-step explanation:
he has $25.00 for the whole week
monday through thursday, or four days, he buys school lunch for $1.50
1.5 x 4 = 6
on friday, he buys 4 slices of pizza for $1.60 per slice
4 x 1.6 = 6.4
Expenses together:
6.4 + 6 = 12.4
Find what he has left:
25-12.4 = 12.6
C. $12.60
Answer:
b
Step-by-step explanation:
B. Y= (x - 10) ^ 4 - 81 OR y = x^4 - 20x +91
We have,
(2y)^3 × y^-1
Simplify the term (2y)^3
= 8y^3 × y^-1
Now, multiply the terms with the same base y by adding their exponents.
Note: Using exponent product rule x^y × x^z = x^(y+z)
= 8y^{3+(-1)}
= 8y^(3-1)
= 8y^(3-1)
= 8y^2