Question

Please need help from math experts!!!! Struggling so hard…

Answer 1

Answer:

Step-by-step explanation:

A(10,10)      B(b,10b)

ax-2y=30

$a)\\a(10)-2(10)=30\\10a-20=30\\10a-20+20=30+20\\10a=50$

Divide both parts of the equation by 10:

a=5

Hence,

5x-2y=30

5(b)-2(10b)=30

5b-20b=30

-15b=30

Divide both parts of the equation by -15:

b=-2

Thus,

a=5     b=-2

$b)\\A(10,10)\ \ \ \ \ \ B(-2,-20)\\ \displaystyle\\C(x_C,y_C)=(\frac{10+(-2)}{2} ,\frac{10+(-20)}{2} )\\\\C(x_C,y_C)=(\frac{10-2}{2},\frac{10-20}{2} )\\\\C(x_C,y_C)=(\frac{8}{2} ,\frac{-10}{2})\\\\C(x_C,y_C)=(4,-5)\\Hence,\ C(4,-5)$

$5x-2y=30\\5x-2y+2y=30+2y\\5x=30+2y\\5x-30=30-30+2y\\5x-30=2y$

Divide both parts of the equation by 2:

2.5x-15=y

$c)\\y=2.5x-15$

               The equation of the perpendiqular bisector

                              $\boxed {y=-\frac{x}{k} +b}$  

Hence,

$\displaystyle\\y=-\frac{x}{2.5}-15 \\\\y=-0.4x-15$