
<h3><u>Analysis </u><u>of </u><u>graph </u><u>:</u><u>-</u></h3>
We have given one graph which is plot between distance and time. where time is in minutes and distance is in seconds.
<u>According </u><u>to </u><u>the </u><u>graph </u>
- For the first 5 minute ( O to A) , The distance is continously increasing 2m / per minute .
- For the 5 minute that is from 5 minute to 13 minute ( A to B) both marellize and her dog wally moving with the constant speed .
- For next 3 minutes that is from 10 minutes to 13 minutes ( B to C) , The distance is continously decreasing with time .
- For next 3 minutes that is from 13 to 16 minutes ( C to D) , Again they moved with constant speed .
- For next 6 minute that is from 16 to 21 minutes ( D to E) . Again, There distance is increasing with time .
- Again For next 4 minutes that is 21 to 25 minutes , they are moving with constant velocity .
<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>
1) Between O and A
- The marellize and wally when moving between O to A , The distance is constantly increasing with time.
- The graph is Straight line
2) Between A and B
- The marellize and wally when moving between A to B, The distance remains the same with time that is they moving with constant speed.
- The graph is constant or steady
3) Between B to C
- The marellize and wally when moving between B to C, The distance is constantly decreasing with time .
- The graph is straight line but it follows decreasing function .
4) For covering the First 6 km ,
<u>According </u><u>to </u><u>the </u><u>graph</u><u>, </u>
- For covering first 6 km, They took 3 minutes.
5) No, Marellize and wally walk does not from where they have started.
<u>According </u><u>to </u><u>the </u><u>graph </u>
- It is end at 5 m instead of 0m .
Answer:
6
Step-by-step explanation:
i cant see the number correctly but the number on the top of the 7 is the answer
Answer:
(√6 - √2)/4
Step-by-step explanation:
cos30°cos45° - sin30°sin45°
= cos (30 + 45)°
= cos 75°
= (√6 - √2)/4
Answer:
880 high-quality version
Step-by-step explanation:
I think the below is your full question:
<em>A Web music store offers two versions of a popular song. The size of the standard version is 2.1megabytes (MB). The size of the high-quality version is 4.5 MB. Yesterday, there were 1290 downloads of the song, for a total download size of 4821 MB. How many downloads of the high-quality version were there?</em>
Here is my answer:
Let x is the number of high-quality version
So the number of standard version= 1290 - x
We also know: total download size of 4821 MB. which means:
4.5x + 2.1(1290-x) = 4821
<=> 4.5x+2709-2.1x=4821
<=> 2.4x=2112
<=> x=880
So there were 880 high-quality version