2. Perpendicular to y=1/2x -6 that passes through (6,-4) PLEASE HELP ME ASAP
1 answer:
Answer:
To get the slope (which we'll call n) of a line perpendicular to another line with slope (a/b), use
Then we just plug in the point we want to cross and solve for the constant.
Step-by-step explanation:
we see that m =
so,
now we have the equation
plugging in (6, -4) we get
This gives us our function
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Answer:
the parabola can be written as:
f(x) = y = a*x^2 + b*x + c
first step.
find the vertex at:
x = -b/2a
the vertex will be the point (-b/2a, f(-b/2a))
now, if a is positive, then the arms of the parabola go up, if a is negative, the arms of the parabola go down.
The next step is to see if we have real roots by using the Bhaskara's equation:
Now, draw the vertex, after that draw the values of the roots in the x-axis, and now conect the points with the general draw of the parabola.
If you do not have any real roots, you can feed into the parabola some different values of x around the vertex
for example at:
x = (-b/2a) + 1 and x = (-b/2a) - 1
those two values should give the same value of y, and now you can connect the vertex with those two points.
If you want a more exact drawing, you can add more points (like x = (-b/2a) + 3 and x = (-b/2a) - 3) and connect them, as more points you add, the best sketch you will have.
Answer:
The Answer:
.
Step-by-step explanation:
x+2y=z
minus x both sides
2y=z-x
divide by 2 both sides
The Answer: