If a used car dealer buys a car for $3 000 and resells it for $3 300 how much has been added to gdp

Pls help with this question

Andreyy89

Answer:

7.01, 10, 7.1, 12, 7.001, 8, 15

Step-by-step explanation:

Those numbers are all greater than 7

7 0

3 years ago

Evaluate g(4): g(x)=8x^2+9x-7 A. 121 B. 135 C. 154 D. 157

inn [45]

The answer is: [D]: " 157" .
________________________________________________________
Explanation:
______________________________________________________

g(x) = 8x² + 9x − 7 ;

g(4) = 8(4²) + 9(4) − 7 ;

= 8(4*4) + 36 − 7 ;

= 8(16) + 36 − 7 ;

= 128 + 36 − 7 ;

= 164 − 7 ;

= 157 .
_______________________________________________________
The answer is: [D]: " 157" .
_______________________________________________________

7 0

3 years ago

Suppose you have a bag containing 2 black marbles and 3 red marbles. You reach into the bag, select a marble, see what color it

TiliK225 [7]

Answer:

$\dfrac{9}{25}$

Step-by-step explanation:

Given that the bag contains black and red marbles.

Number of black marbles in the bag = 2

Number of red marbles in the bag = 3

Total number of marbles in the bag = Number of black marbles + Number of red marbles = 2 + 3 = 5

Let us have a look at the formula for probability of an event E, which can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(\text{First red marble}) = \dfrac{\text{Number of red marbles}}{\text{Total number of marbles}} = \dfrac{3}{5 }$

Now, the marble chosen at first is replaced.

Therefore, the count remains the same.

$P(\text{Second red marble}) = \dfrac{\text{Number of red marbles}}{\text{Total number of marbles}} = \dfrac{3}{5}$

Now, the required probability can be found as:

$P(\text{First red marble})\times P(\text{Second red marble}) = \dfrac{3}{5}\times \dfrac{3}{5} = \bold{\dfrac{9}{25} }$

3 0

3 years ago

What is the difference in hours and minutes between these times 10:35 2:40

MA_775_DIABLO [31]

Answer:

10:35

11:35

12:35

1:35

2:35

=Thats 4 hours

and then 40-35=5

So 4hours 5 minutes

3 0

3 years ago

Read 2 more answers

The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.

Mama L [17]

Answer:

a) P(Y > 76) = 0.0122

b) i) P(both of them will be more than 76 inches tall) = 0.00015

ii) P(Y > 76) = 0.0007

Step-by-step explanation:

Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.

To find - (a) If a man is chosen at random from the population, find

the probability that he will be more than 76 inches tall.

(b) If two men are chosen at random from the population, find

the probability that

(i) both of them will be more than 76 inches tall;

(ii) their mean height will be more than 76 inches.

Proof -

a)

P(Y > 76) = P(Y - mean > 76 - mean)

= P( $\frac{( Y- mean)}{S.D}$ ) > $\frac{( 76- mean)}{S.D}$ )

= P(Z > $\frac{( 76- mean)}{S.D}$ )

= P(Z > $\frac{76 - 69.7}{2.8}$ )

= P(Z > 2.25)

= 1 - P(Z ≤ 2.25)

= 0.0122

⇒P(Y > 76) = 0.0122

b)

(i)

P(both of them will be more than 76 inches tall) = (0.0122)²

= 0.00015

⇒P(both of them will be more than 76 inches tall) = 0.00015

(ii)

Given that,

Mean = 69.7,

$\frac{S.D}{\sqrt{N} }$ = 1.979899,

Now,

P(Y > 76) = P(Y - mean > 76 - mean)

= P( $\frac{( Y- mean)}{\frac{S.D}{\sqrt{N} } }$ )) > $\frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } }$ )

= P(Z > $\frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } }$ )

= P(Z > $\frac{( 76- 69.7)}{1.979899 }$ ))

= P(Z > 3.182)

= 1 - P(Z ≤ 3.182)

= 0.0007

⇒P(Y > 76) = 0.0007

6 0

3 years ago