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2 years ago

Help ASAP (find the area)

Mathematics

1 answer:

vova2212 [387]2 years ago

4 0

Area of pyramid is $168 cm^2$

Here in the diagram is pyramid which is made by triangle and rectangle.

What is the pyramid?

A pyramid is a polyhedron for which the base is a polygon and all lateral faces are triangles.

From figure we have:

AB = 8 cm, AC = 6 cm, BC = 10 cm

And height h = 5 cm

Now area of triangle = 1/2×AB×AC

= 1/2×8×6

=24 cm^2

And perimeter of triangle = 8 + 6 + 10

= 24 cm

Now area of pyramid = 24×5 + 2×24

= 168 cm^2

Hence Area of given figure is $168cm^2$ .

Learn more about the area of pyramid visit:

https://brainly.in/question/7800461

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Which of the following describes a ratio of actual events to the number of trials in an experiment? Select all that apply. HELP

aleksklad [387]

Experiental probability is the correct choice because you will have actual data from an experiment that you are using to create the ratio of outcomes to attempts. This is the scientific and mathematical name for a tested ratio. Theoretical probability, on the other hand, is what you would expect to happen if you were to perform the test.

5 0

3 years ago

Some 1 plz HELP! 3 5/6 X 4 4/5 (plz include instructions if u can thx!)

rewona [7]

Well convert 3 5/6 to 23/6 and 4 4/5 to 24/ 5
then find a multiple that both 5 and 6 have which is 30
23x5= 115 and 24x6= 144
so 115 x 144= 16560/30
16560/30 = 552 /1 so your answer is
552

8 0

3 years ago

Read 2 more answers

Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be

Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of $t=0.6482$

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

$h(t)=-16t^2 +v_{o}t+s$ Eqn(1).

Where:

$h(t)$ : is the height range as a function of time

$v_{o}$ : is the initial velocity

$s$ : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

$h(t)=-16t^2 + v_{o}t + 40$ Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

Ben:

We know that $v_{o}=60ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+60t+40$ Eqn.(3)

Josh:

We know that $v_{o}=48ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+48t+40$ Eqn. (4).

Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at $h(t)=0$ . Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one.

Thus we have for Ben, Eqn. (3) gives:

$h(t)=0-16t^2+60t+40=0$

Using the quadratic expression to find the roots of the quadratic we have:

$t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec$