Answer:
Step-by-step explanation:
Let's call hens h and ducks d. The first algebraic equation says that 6 hens (6h) plus (+) 1 duck (1d) cost (=) 40.
The second algebraic equations says that 4 hens (4h) plus (+) 3 ducks (3d) cost (=) 36.
The system is
6h + 1d = 40
4h + 3d = 36
The best way to go about this is to solve it by substitution since we have a 1d in the first equation. We will solve that equation for d since that makes the most sense algebraically. Doing that,
1d = 40 - 6h.
Now that we know what d equals, we can sub it into the second equation where we see a d. In order,
4h + 3d = 36 becomes
4h + 3(40 - 6h) = 36 and then simplify. By substituting into the second equation we eliminated one of the variables. You can only have 1 unknown in a single equation, and now we do!
4h + 120 - 18h = 36 and
-14h = -84 so
h = 6.
That means that each hen costs $6. Since the cost of a duck is found in the bold print equation above, we will sub in a 6 for h to solve for d:
1d = 40 - 6(6) and
d = 40 - 36 so
d = 4.
That means that each duck costs $4.
Answer:
20%
Since Emily gave 15 of her buttons out of 75, it's just 15/75 or 1/5 which is 20
Step-by-step explanation:
Answer:
at least 20 rows.
Step-by-step explanation:
when you add the students, teachers, and chaperones, it comes to 159. then you divide 159 by the number of seats each row has, so 159/8 = 19.875, you would have to round to the nearest whole number so 20 should be correct.
The distance between them is 9.
<h3>C. <u>x > 42 </u></h3>
<u>Hope</u><u> </u><u>this will</u><u> </u><u>help</u><u>.</u><u>.</u><u>.</u><u> </u>
