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Stolb23 [73]
2 years ago
6

What is the reactive intermediate in the reaction of 1,3-diene with hbr, resulting in 1,4-addition?

Chemistry
1 answer:
viktelen [127]2 years ago
8 0

An allylic carbocation is a reactive intermediate in the reaction of 1,3-diene with her, resulting in 1,4-addition.

<h3>What is carbocation?</h3>
  • A molecule called a carbocation has three bonds and a positively charged carbon atom.
  • They are essentially carbon cations, to put it simply.
  • It was once referred to as carbonium ion.
  • Any even-electron cation with a sizable positive charge on the carbon atom is now referred to as a carbocation.
<h3>Why are carbohydrate molecules crucial?</h3>
  • Because charge can be exchanged between many atoms when the vacant p orbital of a carbocation overlaps with the p orbitals of another carbon-carbon double or triple bond, carbocations next to other carbon-carbon double or triple bonds are very stable.

Learn more about carbocation here:

brainly.com/question/13164680

#SPJ4

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Answer:

Do to half of the mnairals this can not be made into a lab there is an error

Explanation:

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What is the number of electrons in the highest principle energy level of an
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8 electrons

Explanation:

as the the 1st period (H and He), it can hold up to 2 electrons. in the 2nd period (Li, Be, B, C, N, O, F and Ne), it can hold up to 8 electrons. Itstops at 6 when it reached O. add the lelectrons that you have

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The quartz in granite begins to melt at 650°C, so if we find a migmatite where quartz has melted in a granitic rock and we know
Elanso [62]

Answer:

d. 26.0 km

Explanation:

If the temperature in the region increases with depth by about 25 °C /km, then at a depth of 2 km the temperature would be 50 °C higher, at a depth of 3 km the temperature would be 75 °C higher and so on.

<u>The only way for finding melted quartz would be if the temperature is at least 650 °C.</u>

  • Temperature = 25 °C /km * Depth

We put the data given by the problem and <u>solve for Depth</u>:

  • 650 °C = 25 °C /km * Depth
  • Depth = 26.0 km
6 0
4 years ago
Which of the following does the arthropod class Arachnida NOT include?
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A particular uranium alloy has a density of 18.75 g/cm3. Please answer the following questions below, providing the explanation
zhannawk [14.2K]

Answer:

  • a) Critical mass of 49 kg of Uranium: 2600 cm³
  • b) Critical mass of 16 kg Uranium: 850 cm³

Comparison:

  • Baseball: 221 cm³
  • Basketball: 7,238 cm³

  • Baseball < Critical mass of 16 kg of uranium < critical mass of 49 kg of uranium < basketball.

Explanation:

To find the volumes of the two <em>samples</em> of uranium alloy, you must use the formula of density:

         Density=\dfrac{mass}{volume}\\\\\\Volume=\dfrac{mass}{density}

<u>a) Critical mass of 49 kg</u>

First, notice that 18.75g/cm³ is the same that 18.75 kg/dm³ (to convert from grams to kg you must divide by 1,000, and to convert from cm³ to dm³ you must divide by 1,000; thus, dividing both numerator an denominator by the same number leaves the fraction unchanged).

Now you can compute:

   Volume=\dfrac{49kg}{18.75kg/dm^3}=2.6dm^3

You can convert to cm³ multiplying by 1,000cm³/dm³.

Thus, volume = 2,600 cm³.

<u>b) Critical mass = 16 kg</u>

      Volume=\dfrac{16kg}{18.75kg/dm^3}=0.85dm^3

Volume = 850cm³

<u>Compare with approximate volumes of a baseball, a volleyball, and a basketball:</u>

You can calculate those volumes by using the formula for the volume of a sphere:

        Volume=\dfrac{4}{3}\pi\times radius^3

For the baseball: radius ≈ 3.75cm

      Volume=\dfrac{4}{3}\pi\times (3.75cm)^3\approx 221cm^3

For the basketball radius ≈ 12.0 cm

     Volume=\dfrac{4}{3}\pi\times (12.0cm)^3approx 221cm^3\approx 7,238cm^3

Thus, the comparison of the volumes is:

Baseball < Crittical mass 16 kg of Uranium 16 kg < Critical mass 49 kg of Uranium  < Basketball

8 0
3 years ago
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