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2 years ago

1. Complete the following Data Table as you conduct the lab

Chemistry

2 answers:

miskamm [114]2 years ago

4 0

Answer:

Do to half of the mnairals this can not be made into a lab there is an error

Explanation:

Alona [7]2 years ago

4 0

Answer:

Do to half of the mnairals this can not be made into a lab there is an error

Explanation:

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Name the functional group in the

zysi [14]

Answer:

the correct answer B. carboxylic acid

Explanation:

carboxylic acid, any of a class of organic compounds in which a carbon (C) atom is bonded to an oxygen (O) atom by a double bond and to a hydroxyl group (―OH) by a single bond. A fourth bond links the carbon atom to a hydrogen (H) atom or to some other univalent combining group.

6 0

2 years ago

You're provided with a bottle labled [CoCl2.6H2O] = 0.056 M in 4.60 M HCl. You heat a small volume of the solution in a hot wate

sweet [91]

Answer: Equilibrium concentration of $[Cl^-]$ at $50^0C$ is 4.538 M

Explanation:

Initial concentration of $CoCl_2$ = 0.056 M

Initial concentration of $Cl^-$ = 4.60 M

The given balanced equilibrium reaction is,

$COCl_2+2Cl^-\rightleftharpoons [CoCl_4]^{2-}+6H_2O$

Initial conc. 0.056 M 4.60 M 0 M 0 M

At eqm. conc. (0.056-x) M (4.60-2x) M (x) M (6x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[CoCl_4]^{2-}\times [H_2O]^6}{[CoCl_2]^2\times [Cl^-]^2}$

Given : equilibrium concentration of $[CoCl_4]^{2-}$ =x = 0.031 M

Concentration of $Cl^-$ = (4.60-2x) M = $(4.60-2\times 0.031)$ =4.538 M

Thus equilibrium concentration of $[Cl^-]$ at $50^0C$ is 4.538 M

8 0

3 years ago

An element crystallizes in a face-centered cubic lattice. If the length of an edge of the unit cell is 0.408 nm, and the density

V125BC [204]

Answer:

Explanation:

For the density of a face-centered cubic:

$Density = \dfrac{4 \times M_w}{N_A \times a^3}$

where

$M_w$ = molar mass of the compound

$N_A=$ avogadro's constant

$a^3 =$ the volume of a unit cell

Given that:

Density $(\rho)$ = 19.30 g/cm³

a = 0.408 nm

a = $0.408 \times 10^{-9} \times 10^{2} \ cm$

a = $4.08 \times 10^ {-8} \ cm$

∴

$19.3 = \dfrac{4 \times M_w}{(6.023 \tmes 10^{23})\times (4.08 \times 10^{-8})^3}$

$M_w= \dfrac{19.3\times (6.023 \times 10^{23})\times (4.08 \times 10^{-8})^3}{4}$

$M_w=197.37 \ g/mol$

Thus, the molar mass of 197.37 g/mol element is Gold (Au).

4 0

2 years ago

The freezing point of diet soda is higher than the freezing point of regular soda, but lower than 0 degrees celcius, the freezin

Zepler [3.9K]

Answer:

Explanation:

Both Diet Soda and regular soda contain sweeteners.

When a solute is dissolved in solution, the solution undergoes *freezing point depression* it freezing point reduces. The magnitude of freezing point depression is directly proportional to the amount of solute in a solution.

Since soda Both regular or diet soda contains more solute than water , their freezing point is will consequently be lower than water

4 0

2 years ago

If the ratio of the length of a rectangle to its width is 3 to 2, what is the

borishaifa [10]

Answer:

Length of a rectangle whose width is 4 inches is

<u>6 inches</u>

Explanation:

Ratio of length to its width is 3 to 2

Let length = L

Let Width = B

L: B = 3 : 2 (given)

$\frac{L}{B} =\frac{3}{2}$

Width ,B = 4

Insert B in above equation

$\frac{L}{B} =\frac{3}{2}$

$\frac{L}{4} =\frac{3}{2}$

cross multiply,

$L = \frac{3}{2}\times4$

L = 6 inches

Conversion(if required) ,

1 inch = 2.54 cm

6 inch = 2.54 (6)

L = 15.24 cm

8 0

2 years ago