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bearhunter [10]
3 years ago
15

PLEASEEEE HELPPP!! Why does one Oxygen atom bond with two Hydrogen atoms to form water? Why don't they bond in a different ratio

?
Chemistry
1 answer:
elena-14-01-66 [18.8K]3 years ago
4 0
Because the Hydrogen and Oxygen have a slight positive and negative charges that attract them to each other. As to why they bond in that ratio is because they're balanced that way, their electrons balance their covalent bond. This ratio of two Hydrogen and one Oxygen is well balanced therefore easily formed
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Why does inhaled air need to be warmed filtered and moistened?
bearhunter [10]
<span>     The body has to do this to make sure and or to prevent damage to the delicate tissues that form the Respiratory System. This is important because </span>Your body's organs, such as your heart and brain, need oxygen-rich blood to work well. (if it gets damaged by the Cold/Dry air you breath in on a daily)<span><span>Respiratory failure </span>also can occur if your lungs can't properly remove carbon dioxide (a waste gas) from your blood. Too much carbon dioxide in your blood can harm your body's organs.

Hopefully i helped ^.^ please mark brainly if its a possibility~
</span>


4 0
3 years ago
15. If you dilute a 6 M solution of HCl from 5 mL to 50mL, what is the concentration of this new solution? (M1V1 = M2V2)
Andreyy89

Answer:

B) 0.6M

Explanation:

               I apologize in advance if it is not correct :l

The (M1V1= M2V2) is given for you to plug in the correct numbers so let's jot this down.

                    (M1*V1= M2*V2)

so they give us 6M which would be our (M1), from this we can also conclude that 5mL is also V1; ( if you notice the M1's and V1's are always found next to eachother). This leads us to our 50mL, this would be our V2 because the volume went from 5mL to 50mL. Now lets put this in order based on what we know.

M1= 6M                                (M1*V1= M2*V2)

V1= 5mL

M2= ?

V2= 50mL

now we plug in what we know into the equation to find the unknown (M2)

                   (6M*5mL= M2*50mL)

now we could do the long math, but I don't think your on brainly to do the hard way. so lets keep it simple!

                   We are going to put the 50mL under the (6M*5mL) for division.

                             \frac{(6M*5mL)}{(50mL)} This is honestly MUCH easier, than manually answering. you just put that in the calculator and it'll give you B) 0.6M

                 

   honestly though I might not know what I'm doing cuz im currently doing my test and decided to answer this question ;)

        Good Luck!

6 0
3 years ago
Chemistry. Will mark Brainly.
kogti [31]

Answer:

c is right

Explanation:

8 0
3 years ago
Which part of the food web is NOT a living thing?
stiks02 [169]

Answer:

the sun

Explanation:

the sun is not alive and plants use photosynthesis to eat the radiation emitted by the sun.

4 0
3 years ago
Calculate the freezing point (in degrees C) of a solution made by dissolving 7.99 g of anthracene{C14H10} in 79 g of benzene. Th
mario62 [17]

<u>Answer:</u> The freezing point of solution is 2.6°C

<u>Explanation:</u>

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

where,

\Delta T_f = \text{Freezing point of pure solution}-\text{Freezing point of solution}

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_f = molal freezing point depression constant = 5.12 K/m  = 5.12 °C/m

m_{solute} = Given mass of solute (anthracene) = 7.99 g

M_{solute} = Molar mass of solute (anthracene) = 178.23  g/mol

W_{solvent} = Mass of solvent (benzene) = 79 g

Putting values in above equation, we get:

5.5-\text{Freezing point of solution}=1\times 5.12^oC/m\times \frac{7.99\times 1000}{178.23g/mol\times 79}\\\\\text{Freezing point of solution}=2.6^oC

Hence, the freezing point of solution is 2.6°C

8 0
3 years ago
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