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bearhunter [10]
3 years ago
15

PLEASEEEE HELPPP!! Why does one Oxygen atom bond with two Hydrogen atoms to form water? Why don't they bond in a different ratio

?
Chemistry
1 answer:
elena-14-01-66 [18.8K]3 years ago
4 0
Because the Hydrogen and Oxygen have a slight positive and negative charges that attract them to each other. As to why they bond in that ratio is because they're balanced that way, their electrons balance their covalent bond. This ratio of two Hydrogen and one Oxygen is well balanced therefore easily formed
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The combustion of magnesium creates so much energy so quickly that it is hard to measure its enthalpy directly using a simple ca
riadik2000 [5.3K]
I believe your answer is: What is the enthalpy of formation of magnesium oxide?
Hope this helps! :)
6 0
3 years ago
Read 2 more answers
A gas mixture contains twice as many moles of o2 as n2. addition of 0.200 mol of argon to this mixture increases the pressure fr
pantera1 [17]
Number of moles of oxygen = x

number of moles of nitrogen = y

x = 2y

initial pressure, p1 = 0.8 atm

final pressure, p2 = 1.10 atm

At constant volume and temperature p1 / n1 = p2 / n2

=> p1 / p2 = n1 / n2

n1 = x + y = 2y + y = 3y

n2 = 0.2 + 3y

=> p1 / p2 = 3y / (0.2 + 3y)

=> 0.8 / 1.10 = 3y / (0.2 + 3y)

=> 0.8 (0.2 + 3y) = 1.10 (3y)

0.16 + 2.4y = 3.3y

=> 3.3y - 2.4y = 0.16

=> 0.9y = 0.16

=> y = 0.16 / 0.9

=. x = 2*0.16/0.9 = 0.356

Answer: 0.356 moles O2
8 0
3 years ago
How many atoms are in 3.690 moles of oxygen
sweet [91]

1 mole of any substance contains Avogadro's number.  

So, 1 mole of O2= 6.023x10^23 molecules  

3 mole of O2= 6.023x10^23x3 molecules  

= 1.8069x10^24 molecules  

Each molecule of Oxygen has 2 atoms.  

therefore,  

1.8069x10^24 molecules= 1.8069x10^24 x 2 atoms  

= 3.6138x10^24 atoms.

4 0
3 years ago
Are there any parts of the human body that get oxygen directly from the air and not from the blood?
n200080 [17]

Answer: Cornea  

Explanation: The cornea is the only part of a human body that has no blood supply as it gets oxygen directly through the air.

3 0
3 years ago
G. Amount of charge required to reduce
Nady [450]

Answer:

\boxed{\text{c) 4 F}}

Explanation:

1. Write the skeleton equation for the half-reaction

NO₃⁻ ⟶ N₂O

2. Balance all atoms other than H and O

2NO₃⁻ ⟶ N₂O

3. Balance O by adding H₂O molecules to the deficient side.

2NO₃⁻ ⟶ N₂O + 5H₂O

4. Balance H by adding H⁺ ions to the deficient side.

2NO₃⁻ + 10H⁺ ⟶ N₂O + 5H₂O

5. Balance charge by adding electrons to the deficient side.

2NO₃⁻ + 10H⁺ + 8e⁻ ⟶ N₂O + 5H₂O

The amount of charge required to reduce 2 mol of NO₃⁻ is 8 F

\text{The amount of charge required to reduce 1 mol of NO$_{3}^{-}$ is \boxed{\textbf{4 F}}}

4 0
2 years ago
Read 2 more answers
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