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lara [203]
1 year ago
5

Please Help Thank You :)

Mathematics
1 answer:
olganol [36]1 year ago
5 0

Considering the area of the right triangle, it is found that Salome used a scale factor of 1/2 to go from triangle R to triangle T.

<h3>What is the area of a right triangle?</h3>

The area of a right triangle is given by half the multiplication of the lengths of it's sides.

In this figure, we have that the sides have lengths of 4 and 5 units, hence the area is given by:

A = 0.5 x 4 x 5 = 10 square units.

The area is one fourth of the area of triangle R. Since we are dealing with an area, that works in squared units, the scale factor is given by:

S = sqrt(1/4) = 1/2.

Hence Salome used a scale factor of 1/2 to go from triangle R to triangle T.

More can be learned about the area of a right triangle at brainly.com/question/28230160

#SPJ1

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Step-by-step explanation:

1 step:

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2 step:

Assume that for n=k the following statement is true

\sum \limits_{j=1}^k2^j=2(2^k-1)

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Start with the left side:

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)

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\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)

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a) \frac{dy}{du}=\frac{d}{du} (u^5)=5u^4=5(x^2 +1)^4 from the power rule.  

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