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Kazeer [188]
3 years ago
11

A small publishing company is planning to publish a new book. The production costs will include one-time fixed costs (such as ed

iting) and variable costs (such as printing). There are two production methods it could use. With one method, the one-time fixed costs will total 58,881 , and the variable costs will be 8.50 per book. With the other method, the one-time fixed costs will total 18,081, and the variable costs will be 21.25 per book. For how many books produced will the costs from the two methods be the same?
Mathematics
1 answer:
zhuklara [117]3 years ago
4 0

Answer:

For the cost from the two methods to be equal, 3,200 books have to be produced

Step-by-step explanation:

In this question, we are asked to calculate the number of books that will be produced for two methods of production having different fixed and variable costs to have the same production cost.

Since the number of books is something we do not know, let’s represent it with a variable called c.

For the first production method, the cost of production will be ; 58,881 + 8.50c

For the second production method, the cost of production will be; 18,081 + 21.25c

Now since they are said to be equal, we proceed to equate both;

58,881 + 8.5c = 18,081 + 21.25c

58,881-18,081 = 21.25c - 8.5c

40,800 = 12.75c

c = 40,800/12.75

c = 3,200 books

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A factory makes rectangular sheets of cardboard, each with an area of 2 1 2square feet. Each sheet of cardboard can be cut into
hodyreva [135]

Answer:

2 1/7 pieces

Step-by-step explanation:

A factory makes rectangular sheets of cardboard, each with an area 2 1/2 square feet. Each sheet of cardboard can be cut into smaller pieces of cardboard measuring 1 1/6 square feet. How many smaller pieces of cardboard does each sheet of cardboard provide?

Each sheet of cardboard = 2 1/2 square feet

Each smaller pieces of cardboard = 1 1/6 square feet

Number of smaller pieces of cardboard per sheet of cardboard = Each sheet of cardboard ÷

Each smaller pieces of cardboard

= 2 1/2 square feet ÷ 1 1/6 square feet

= 5/2 ÷ 7/6

= 5/2 × 6/7

= (5*6) / (2*7)

= 30/14

= 15/7

= 2 1/7 pieces

Number of smaller pieces of cardboard per sheet of cardboard = 2 1/7 pieces

6 0
3 years ago
A 6-yard piece of ribbon costs $36.72. What is the price per foot?
djyliett [7]

Answer:

$2.04

Step-by-step explanation:

Note that: 1 yard = 3 feet.

First, change the amount of yard (6) to feet:

6 x 3 = 18

6 yard = 18 feet.

Note: 18 feet = $36.72

Find the cost per foot (1 feet). Note the equal sign, what you do to one side, you do to the other. Divide 18 from both sides.

(18 ft)/18 = ($36.72)/18

1 ft = 36.72/18

1 ft = 2.04/1

1 ft = $2.04

~

4 0
3 years ago
Read 2 more answers
Line CD contains points A (4, -7) and B (4, 8). The slope of line CD is
mylen [45]
<span>To find the slope, you divide the difference of the y-coordinates of a point on a line by the difference of the x-coordinates. It is expressed as:

slope = (y2 - y1) / (x2-x1)
slope = 8-(-7) / 4 - 4
slope = 15 / 0
slope = undefined <------ SECOND OPTION

The line should be vertical where the slope is undefined. Hope this answers the question. Have a nice day.</span>
6 0
3 years ago
Read 2 more answers
Dylan's expenditures for each of the past six months were: March $1,248.59; April, $1,365.38; May, $1,024.30; June, $1,100.40; J
ivann1987 [24]

Answer:

The average monthly expenditure is 1,155.35 $.

Step-by-step explanation:

The average of any sequency is given by the sum of it's individual parts divided by the number of parts it has. So in this case the average of monthly expenditure will be the sum of all individual expenditures divided by the number of months. The question can be solved like this:

average = (March+ April + May + June + July+ August)/6

average = (1,249.59 + 1,365.38 + 1,024.3 + 1,100.4 + 992,4 + 1,200.02)/6

average = 1,155.35 $

3 0
3 years ago
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Is 4-heap Nim with heaps of sizes 22, 19, 14, and 11 balanced or unbalanced? Player I's first move is to remove 6 coins from the
nadya68 [22]

Answer:

Player II should remove 14 coins from the heap of size 22.

Step-by-step explanation:

To properly answer this this question, we need to understand the principle and what it is exactly is being asked.

This question revolves round a game of Nim

What is a game of Nim: This is a strategic mathematical game whereby,  two opposing sides or opponent take turns taking away objects from a load or piles. On each turn, a player remove at least an object and may remove any number of objects provided they all come from the same heap/pile.

Now, referring back to the question, we should first understand that:

                        22₂ = 1 0 1 1 0

                         19₂= 1 0 0 1 1

                         14₂= 0 1 1 1 0

                          11₂= 0 1 0 1 1

and also that the “bit sums” are all even, so this is a balanced game.

However, after Player I removes 6 coins from the heap of size 19, Player II should remove 14 coins from the heap of size 22.

3 0
3 years ago
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