All categories

2 years ago

PLEASE PLEASE HELP MEE!!!

Mathematics

1 answer:

rewona [7]2 years ago

5 0

Area of part 1:A1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2Area of part 2:A2=length*width=(8+2)*1=10 ft2Area of part 3:A3=length*width=8*2=16 ft2
Total shaded area : A1+A2+A3=41 ft2Total area of the reactangle : A=16*8=128 ft2Total area of the nonshaded region : 128-41=87 ft2

You might be interested in

PLEASE HELP step by step

Katen [24]

Answer:

The length of the line segment is 10 units.

Step-by-step explanation:

Let us call the given two points: (x₁, y₁) = (2, -3) and (x₂, y₂) = (8, 5).

The distance between two points, d = $\sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2} }$

Here, $(x_1, y_1) = (2, -3)$ and

$(x_2, y_2) = (8, 5)$

Therefore, distance, d = $\sqrt{(8 - 2)^2 + (5 - (-3))^2$

$= \sqrt{6^2 + 8^2}$

$= \sqrt{36 + 64}$

$= \sqrt{100}$

= 10 units.

Hence, the answer.

3 0

3 years ago

Find x and y please!!! I need help!!

jonny [76]

Answer

Step-by-step explanation:

(15x-8y)=52

180=90+52+x

x=38

System of equations:

15x-8y=52

6x+14y=38

y=-6.5+15/8x

6x+14(-6.5+15/8x)=38

6x-91+26.25x=38

32.25x=129

x=4

15(4)-8y=52

60-8y=52

-8y=-8

y=1

x=4

7 0

2 years ago

What is the force of gravity (in Newtons) acting between the Earth and a 100-kg person who is on board the International Space S

ratelena [41]

Answer:

$f_{G}=317877.55 N = 317.8 kN$

Step-by-step explanation:

$f_{G}= (G*m_{1}*m_{2})/r^{2} \\Where:\\f_{G}= force of gravity\\G=gravitational constant= 6.6x10^{-11}m^{3}kg^{-1}s^{-2}\\ m_{1}= earth mass = 5.9x10^{24}kg\\m_{2}=person mass = 100kg\\r= distance between the bodies=350km= 350 000 m$