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sashaice [31]
2 years ago
5

A gumball is approximately spherical and has a diameter of 1 inch. What is the approximate volume of the gumball? A gumball is a

pproximately spherical and has a diameter of 1 inch. What is the approximate volume of the gumball? 0.369 in3 0.758 in3 0.5236 in3 0.423 in3
Mathematics
1 answer:
KatRina [158]2 years ago
5 0

The approximate volume of the spherical gumball is: C. 0.5236 in.³.

<h3>How to Determine the Volume of a Spherical Shape?</h3>

If a shape is spherical, it means it has a shape of a sphere. To determine the volume of the spherical shape, we would use the formula for the volume of a sphere, which is given as:

Volume of a sphere = 4/3 × π × r³, where r (radius of the sphere) is half of the diameter of the sphere.

Given the following parameters of the sphere as:

Diameter of sphere = 1 inch.

Radius (r) = 1/2(1) = 0.5 inch.

π = 3.14

To find the approximate volume of the spherical gumball, substitute the value of r into 4/3 × π × r³:

Volume of the spherical gumball = 4/3 × 3.14 × 0.5³

Volume of the spherical gumball = 4/3 × 3.14 × 0.125

Volume of the spherical gumball = (4 × 3.14 × 0.125)/3

Volume of the spherical gumball = (1.57)/3

Volume of the spherical gumball = 0.523 in.³

Therefore, we can conclude that the approximate volume of the spherical gumball is: C. 0.5236 in.³.

Learn more about volume of sphere on:

brainly.com/question/22807400

#SPJ1

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4.58258

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Simplify the expression state any excluded values<br> 2a^2-4a+2<br> ---------------<br> 3a^2-3
chubhunter [2.5K]

Answer:

The simplified form is \dfrac{2(x-1)}{3(x+1)}.

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Step-by-step explanation:

Given:

The expression given is:

\dfrac{2a^2-4a+2}{3a^2-3}

Let us simplify the numerator and denominator separately.

The numerator is given as 2a^2-4a+2

2 is a common factor in all the three terms. So, we factor it out. This gives,

=2(a^2-2a+1)

Now, a^2-2a+1=(a-1)(a-1)

Therefore, the numerator becomes 2(a-1)(a-1)

The denominator is given as: 3a^2-3

Factoring out 3, we get

3(a^2-1)

Now, a^2-1 is of the form a^2-b^2=(a-b)(a+b)

So, a^2-1=(a-1)(a+1)

Therefore, the denominator becomes 3(a-1)(a+1)

Now, the given expression is simplified to:

\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}

There is (x-1) in the numerator and denominator. We can cancel them only if x\ne1 as for x=1, the given expression is undefined.

Now, cancelling the like terms considering x\ne1, we get:

\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}

Therefore, the simplified form is \dfrac{2(x-1)}{3(x+1)}

The simplification is true only if  x\ne1. So, x =1 is the excluded value for the given expression.

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