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skad [1K]
3 years ago
13

I need help with this algebra question

Mathematics
2 answers:
ioda3 years ago
7 0

Answer:

4.58258

Step-by-step explanation:

Pythagorean Theorem:

a² + b² = c²

Input:

2² + x² = 5²

Remember, c² is always the side opposite of the right angle...

4 + x² = 25

21 = x²

x = 4.58258

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

dybincka [34]3 years ago
3 0

Answer:

\sqrt{21}

Step-by-step explanation:

let the missing side be x , then

Using Pythagoras' identity in the right triangle.

x² + 2² = 5²

x² + 4 = 25 ( subtract 4 from both sides )

x² = 21 ( take the square root of both sides )

x = \sqrt{21} ≈ 4.6 ( to 1 dec. place )

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A triangle has the following measurements: B=79 degrees a=5ft
11Alexandr11 [23.1K]
The law of cosines for this particular situation is b^2 = a^2 + c^2 - 2ac cosB.
Filling in what you know, you have b^2 = 25 + 49 - [2(5)(7)-.1908], which simplifies to b^2 = 74 - 69.8092 which gives you a b^2 value of 4.1908, but you have to take the square root of that so you get a side value for b of 2.05.
6 0
3 years ago
A company manufactures and sells x television sets per month. The monthly cost and price-demand equations are
skelet666 [1.2K]

A) The maximum revenue is 450000$

B) The maximum profit is 216000$ when 2400 sets are manufactured and sold for 180$ each

C) When each set is taxed at ​$55​, the maximum profit is 99125$ when 1850 sets are manufactured and sold for 207.5$ each.

A)p(x)=300−(x/20​),

revenue R(x)=p*x

revenue R(x)=300x -(x2/20)

for maximum revenue dR/dx =0 ,

=>300-(2x/20)=0

=>x/10=300

=>x=3000

maximum revenue = R(3000)=300*3000 -(30002/20)

maximum revenue = R(3000)=450000$

B) profit =revenue -cost

profit P(x)=300x -(x2/20)-72000-60x

profit P(x)=240x -(x2/20)-72000

for maximum cost dP/dx =0

240 -(2x/20)=0

x=240*10

x=2400

p(2400)=300−(2400/20​)=180

profit P(2400)=240*2400 -(24002/20)-72000 =216000

The maximum profit is 216000$ when 2400 sets are manufactured and sold for 180$ each

c)

profit =revenue -cost -tax

profit P(x)=300x -(x2/20)-72000-60x-55x

profit P(x)=185x -(x2/20)-72000

for maximum cost dP/dx =0

185-(2x/20)=0

x=185*10

x=1850

p(1850)=300−(1850/20​)=207.5

profit P(1850)=185*1850 -(18502/20)-72000

profit P(1850)=99125$

When each set is taxed at ​$55​, the maximum profit is 99125$ when 1850 sets are manufactured and sold for 207.5$ each.

To know more about maximum profit check the below link:

brainly.com/question/4166660

#SPJ4

5 0
1 year ago
10) Find the measure of angle D. Hint: you must do two math problems to solve
NISA [10]

Answer:

Option A.) 43°

Step-by-step explanation:

Part 10)

step 1

Find the length of side EG

see the attached figure to better understand the problem

we know that

In the right triangle EGF

cos(65^o)=\frac{EG}{EF} ----> by CAH (adjacent side divided by the hypotenuse)

substitute the given values

cos(65^o)=\frac{EG}{11}

solve for EG

EG=(11)cos(65^o)\\EG=4.65\ cm

step 2

Find the measure of angle D

In the right triangle DEG

tan(D)=\frac{EG}{DG} ----> by TOA (opposite side divided by adjacent side)

substitute the given values

tan(D)=\frac{4.65}{5}\\\\D=tan^{-1}(\frac{4.65}{5})=43^o

3 0
3 years ago
Write the equation y=3/4x+4 in standard form
LenKa [72]

Answer:

3x-4y=-16

Step-by-step explanation:

3 0
3 years ago
19,050,000 in scientific notation
Marizza181 [45]
=1.905 x 10^7 I believe!
4 0
3 years ago
Read 2 more answers
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