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r-ruslan [8.4K]
1 year ago
11

practice factoring a difference of squares. which expressions represent a perfect square monomial and its square root? check all

that apply. 121; 11 4x2; 2x 9x2 – 1; 3x - 1 25x; 5x 49x4; 7x2
Mathematics
1 answer:
ohaa [14]1 year ago
8 0

The perfect square monomial and its square root are shown in options 1, 2, and 5.

  • A perfect square in mathematics is an expression that factors into two equally valid expressions. A monomial is a single phrase that is made up of the product of positive integer powers of the constants, variables, and constants. Consequently, a monomial that factors into two monomials that are the same is called a perfect square monomial.
  • 1) 121, 11
  • 11² = 121
  • A perfect square monomial and its square root are represented by this equation.
  • 2) 4x², 2x
  • (2x)² = 4x²
  • A perfect square monomial and its square root are represented by this equation.
  • 3) 9x²-1, 3x-1
  • (3x-1)² = 9x²- 6x +1
  • This phrase does not depict a square monomial and its square root in perfect form.
  • 4) 25x, 5x
  • (5x)² = 25x²
  • This phrase does not depict a square monomial and its square root in perfect form.
  • 5) 49(x^4), 7x²
  • (7x²)² = 49(x^4)
  • A perfect square monomial and its square root are represented by this equation.

To learn more about monomial, visit :

brainly.com/question/9183135

#SPJ4

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Answer:

P(X \geq 2) = 1-P(X

And we can find the individual probabilities using the probability mass function and we got:

P(X=0) = (30C0) (0.05)^0 (1-0.05)^{30-0} =0.2146

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Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

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The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

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Solution to the problem

For this case we want this probability:

P(X \geq 2)

And we can use the complement rule and we got:

P(X \geq 2) = 1-P(X

And we can find the individual probabilities using the probability mass function and we got:

P(X=0) = (30C0) (0.05)^0 (1-0.05)^{30-0} =0.2146

P(X=1) = (30C1) (0.05)^1 (1-0.05)^{30-1} = 0.3389

And replacing we got:

P(X \geq 2) = 1-P(X

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