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Rina8888 [55]
4 years ago
11

Given that the two triangles are similar, solve for x if AU = 20x + 108, UB = 273, BC = 703, UV = 444, AV = 372 and AC = 589. Yo

u must show all of your work to receive credit.
Mathematics
1 answer:
Arlecino [84]4 years ago
4 0

If two triangles are similar then the corresponding sides are in proportion. Thus,

AB / AU = BC / UV = AC / AV

AB / (20x+108) = 703 / 444

Where AB is equivalent to:

AB = AU + UB

AB = 20x + 108 + 273

AB = 20x + 381

Therefore going back to the first equation:

(20x + 381) / (20x + 108) = 703/444

444 (20x + 381) = 703 (20x + 108)

8880x + 169164 = 14060x + 75924

14060x - 8880x = 169164 – 75924

5180 x = 93240

x = 93240 / 5180

<span>x = 18</span>

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Solve for y:<br> x + 2y = -8<br><br> y=-1/2x+4<br> y=-1/2x-4<br> y=-2x - 4<br> y=1/2x-4
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Answer:

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Step-by-step explanation:

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x+2y=-8\\2y=-8-x\\y=-4-\frac{1}{2}x\\

4 0
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Slope Intercept Form And Equations From Graphs
r-ruslan [8.4K]

Answer:

1. Choice B

2.  Choice C

3.  X=-2

4.  Choice A

5. y = 5/2 x + 5

Step-by-step explanation:

1.  

   the slope is down 3 over 2     m =-3/2

point slope form

y-y1= m (x-x1)

y-y1 = -3/2 (x-x1)

Choice B


2.  (-3,-1)  (1/2,2)

slope = (y2-y1)/(x2-x1)

m=(2--1)/(1/2--3)  = (2+1)/(1/2+3) = 3/(3.5) =  multiply top and bottom by 2

  m = 6/7

point slope form

y-y1 = m(x-x1)

y--1 = 6/7 (x--3)

y+1 =6/7 (x+3)

multiply by 7

7y+7 = 6(x+3)

7y+7 = 6x+18

subtract 7y from each side

7 = 6x-7y+18

subtract 18 from each side

-11=6x-7y

Choice C


3.  x=-2

This is a vertical line, the value of x never changes


4.   (-1,2) (1,-4)

slope =(y2-y1)/(x2-x1)

      = (-4-2)/(1--1) = -6/(1+1) = -6/2 = -3

point slope form

y-y1 = m(x-x1)

y-2 = -3(x--1)

y-2 = -3(x+1)

y-2 = -3x-3

add 2 to each side

y = -3x-1

Choice A


5.  (-2,0)  (0,5)

the y intercept is 5

slope is change in y over change in x

slope =(y2-y1)/(x2-x1)  = (0-5)/(-2-0) = -5/-2 = 5/2

slope intercept form

y= mx+b

y = 5/2 x + 5



7 0
3 years ago
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