Bro ? What is this ? Rocket science ? HELP ME PLSSS.

Elisa bought 5 bracelets for a total of $25.95. If the bracelets were the same cost, about how much did each bracelet cost?

Lady bird [3.3K]

Answer:

Step-by-step explanation:

To find out what each bracelet costed, you have to divide the total amount spent by how many bracelets were purchased.

25.95 ÷ 5 = 5.19

In conclusion, each bracelet cost $5.19. :)

4 0

2 years ago

This is what i need help with thanks

lawyer [7]

B
Hope this helped you

7 0

2 years ago

Read 2 more answers

5. Average (missing value). The temperature at the top of Mt. Hood in Oregon was recorded for 5 straight days. For the first fou

Nata [24]

Answer:

5°F

Step-by-step explanation:

Given that the average is obtained from;

Average = sum of scores / number of scores

Average temperature = 19.8°F

Let the temperature of the fifth day be x

Hence;

19.8 = 32 + 30 + 22 + 10 + x/5

19.8 = 94 + x/5

x= (5×19.8) -94

x= 5°F

4 0

3 years ago

Hello ! I need a solution for this exercise: either 1≤x≤2 and let A = -3 + 8 / (x + 1) -2x² Show that -9≤A≤-1

Phantasy [73]

\left[A \right] = \left[ \frac{ - \left( 5 - 3\,x - 2\,x^{2} - 2\,x^{3}\right) }{-1-x}\right][A]=[−1−x−(5−3x−2x2−2x3)] I hope helping this answer

6 0

2 years ago

Find the equation of the sphere if one of its diameters has endpoints (4, 2, -9) and (6, 6, -3) which has been normalized so tha

Pavel [41]

Answer:

$(x - 5)^2 + (y - 4)^2 + (z - 6)^2 = 14$ .

(Expand to obtain an equivalent expression for the sphere: $x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0$ )

Step-by-step explanation:

Apply the Pythagorean Theorem to find the distance between these two endpoints:

$\begin{aligned}&\text{Distance}\cr &= \sqrt{\left(x_2 - x_1\right)^2 + \left(y_2 - y_1\right)^2 + \left(z_2 - z_1\right)^2} \cr &= \sqrt{(6 - 4)^2 + (6 - 2)^2 + ((-3) - (-9))^2 \cr &= \sqrt{56}}\end{aligned}$ .

Since the two endpoints form a diameter of the sphere, the distance between them would be equal to the diameter of the sphere. The radius of a sphere is one-half of its diameter. In this case, that would be equal to:

$\begin{aligned} r &= \frac{1}{2} \, \sqrt{56} \cr &= \sqrt{\left(\frac{1}{2}\right)^2 \times 56} \cr &= \sqrt{\frac{1}{4} \times 56} \cr &= \sqrt{14} \end{aligned}$ .

In a sphere, the midpoint of every diameter would be the center of the sphere. Each component of the midpoint of a segment (such as the diameter in this question) is equal to the arithmetic mean of that component of the two endpoints. In other words, the midpoint of a segment between $\left(x_1, \, y_1, \, z_1\right)$ and $\left(x_2, \, y_2, \, z_2\right)$ would be:

$\displaystyle \left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right)$ .

In this case, the midpoint of the diameter, which is the same as the center of the sphere, would be at:

$\begin{aligned}&\left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right) \cr &= \left(\frac{4 + 6}{2},\, \frac{2 + 6}{2}, \, \frac{(-9) + (-3)}{2}\right) \cr &= (5,\, 4\, -6)\end{aligned}$ .