Ask question

Ask question

All categories

2 years ago

7

Show how to solve -5y+8=-3y+10

2 answers:

marta [7]2 years ago

8 0

-5y+8=-3y+10
-5y+3y=10-8
-2y=2
-2y/-2=2/-2
y=-1

I grouped the alike variable to one side, and the number to the other side, added and subtracted it, divided both sides by -2, and got -1

Whitepunk [10]2 years ago

7 0

-5y+3y=10-8
-2y=2 (divide by -2 both sides)
Y=-1

You might be interested in

when full the gas tank of a car holds 15 gallons. it now contains 12 gallons. what percent represents how full the tank is?

Masteriza [31]

Hello!

to find the percent of a whole, use this equation here:

(remaining) / (total) = X

X * 100 = %

in this case:

12 / 15 = 0.8

0.8 * 100 = 80

your answer is 80%

I hope this helps, and have a nice day!

5 0

2 years ago

Rewrite as a simplified fraction.<br> 0.83 = 8/9

mina [271]

it is in the smallest form!

4 0

3 years ago

If line segment BC is considered the base of triangle ABC, what is the corresponding height of the triangle?

Leni [432]

Answer:

1.6 units

Step-by-step explanation:

Coordinates of A : (-1,1)

Coordinates of B : (3,2)

Coordinates of C :( -1,-1)

Now to find the length of the sides of the triangle we will use distance formula :

$d =\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

To find length of AB

A = $(x_1,y_1)=(-1,1)$

B= $(x_2,y_2)=(3,2)$

Now substitute the values in the formula:

$d =\sqrt{(3-(-1))^2+(2-1)^2}$

$d =\sqrt{(4)^2+(1)^2}$

$d =\sqrt{16+1}$

$d =\sqrt{17}$

$d =4.12$

Now to find length of BC

B= $(x_1,y_1)=(3,2)$

C = $(x_2,y_2)=(-1,-1)$

Now substitute the values in the formula:

$d =\sqrt{(-1-3)^2+(-1-2)^2}$

$d =\sqrt{(-4)^2+(-3)^2}$

$d =\sqrt{16+9}$

$d =\sqrt{25}$

$d =5$

Now to find length of AC

A = $(x_1,y_1)=(-1,1)$

C = $(x_2,y_2)=(-1,-1)$

Now substitute the values in the formula:

$d =\sqrt{(-1-(-1))^2+(-1-1)^2}$

$d =\sqrt{(0)^2+(-2)^2}$

$d =\sqrt{4}$

$d =2$

Thus the sides of triangle are of length 4.12, 5 and 2

Now to find area of triangle we will use heron's formula :

To calculate the area of given triangle we will use the heron's formula :

$Area = \sqrt{s(s-a)(s-b)(s-c)}$

Where $s = \frac{a+b+c}{2}$

a,b,c are the side lengths of triangle

a = 4.12

b=5

c=2

Substitute the values

Now substitute the values :

$s = \frac{4.12+5+2}{2}$

$s =5.56$

$Area = \sqrt{5.56(5.56-4.12)(5.56-5)(5.56-2)}$

$Area = 3.99$

Now to find the height of altitude corresponding to side BC

So, formula of area of triangle $=\frac{1}{2} \times Base \times Height$

Since Area = 3.99 square units

So, $3.99 =\frac{1}{2} \times BC \times Height$

So, $3.99 =\frac{1}{2} \times 5\times Height$

$3.99 =2.5 \times Height$

$\frac{3.99}{2.5}=Height$

$1.596=Height$

Thus the altitude corresponding to the BC is of length 1.596 unit ≈ 1.6 units

Thus Option D is correct.

7 0

2 years ago

Read 2 more answers

Which is the balanced equation for S3 + O2 – SO2?

Shkiper50 [21]

The answer is not in the option. This is the answer
S3 + 3O2 ——-> 3SO2

6 0

3 years ago

I need help plz!!!!!!!

RSB [31]

You'll first need to calculate the measure of angle R. From the diagram we see that
opp 33
tan R = ------- = ----- = 0.589, so, using the inv. tang. function, R = 0.589 rad.
adj 56
opp 33
Then sin R = --------- = sin 0.589 rad = ------------------------- = 0.508 rad
hyp sqrt(33^2 + 56^2)

or 29.089 degrees

7 0

3 years ago