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mr Goodwill [35]

2 years ago

8

Who runs the fastest

2 answers:

Salsk061 [2.6K]2 years ago

6 0

Ron is the one that runs the fastest I’ve calculated every single option and that’s the fastest

klemol [59]2 years ago

4 0

Answer:

Ron run faster then other

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If cos Θ = square root 2 over 2 and 3 pi over 2 < Θ < 2π, what are the values of sin Θ and tan Θ? sin Θ = square root 2 ov

densk [106]

Answer:

$\huge\boxed{\sin\theta=-\dfrac{\sqrt2}{2};\ \tan\theta=-1}$

Step-by-step explanation:

We have:

$\\cos\theta=\dfrac{\sqrt2}{2},\ \dfrac{3\pi}{2}$

For sine use:

$\sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x$

Substitute:

$\sin^2\theta=1-\left(\dfrac{\sqrt2}{2}\right)^2\\\\\sin^2\theta=1-\dfrac{(\sqrt2)^2}{2^2}\\\\\sin^2\theta=1-\dfrac{2}{4}\\\\\sin^2\theta=\dfrac{4}{4}-\dfrac{2}{4}\\\\\sin^2\theta=\dfrac{4-2}{4}\\\\\sin^2\theta=\dfrac{2}{4}\to\sin\theta=\pm\sqrt{\dfrac{2}{4}}\\\\\sin\theta=\pm\dfrac{\sqrt2}{\sqrt4}\\\\\sin\theta=\pm\dfrac{\sqrt2}{2}$

θ in IV quadrant, therefore sine is negative.

$\sin\theta=-\dfrac{\sqrt2}{2}$

For tangent use:

$\tan x=\dfrac{\sin x}{\cos x}$

Substitute:

$\tan\theta=\dfrac{-\frac{\sqrt2}{2}}{\frac{\sqrt2}{2}}=-\dfrac{\sqrt2}{2}\cdot\dfrac{2}{\sqrt2}=-1$

8 0

3 years ago

If a=5x^2+3x-7 and b=-3x^2-7x+5 find b-a

uranmaximum [27]

Answer:

-8x^2-10x+12

Step-by-step explanation:

first set up the problem:

(-3x^2-7x+5)-(5x^2+3x-7)

Since you are subtracting you need to distribute the (-) sign:

(-3x^2‐7x+5)(-5x^2-3x+7)

Now just combine like terms

-3x^2+(-5x^2= -8x^2

(-7x+(-3x= -10x

5+7= 12

set answer in standard form:

-8x^2-10x+12

3 0

3 years ago

During summer vacation, you charge people $8 per hour for babysitting and $10 for going to their house. If you make $50 one day,

Inessa05 [86]

5 hours is the answer

7 0

3 years ago

Read 2 more answers

URGENT! PLEASE help me! Full solutions please, and no nonsense answers.

valentinak56 [21]

Answer:

$\frac{1}{3x+52}$

Step-by-step explanation:

Given

$\frac{\frac{1}{x^2+51x+50} }{\frac{2}{x+50}+\frac{1}{x+1} }$

= $\frac{\frac{1}{(x+50)(x+1)} }{\frac{2(x+1)+x+50}{(x+50)(x+1)} }$

= $\frac{1}{(x+50)(x+1)}$ × $\frac{(x+50)(x+1)}{2x+2+x+50}$ ← cancel (x + 50)(x + 1) on numerator/denominator

= $\frac{1}{3x+52}$

8 0

3 years ago

Read 2 more answers

3ab<br> 1. monomial<br> 2. binomial<br> 3. trinomial<br> 4. none of these

san4es73 [151]

It’d be a binomial because there are two different terms (a and b)

6 0

3 years ago