Answer:
C. f(x)=3(1/2)^x
Step-by-step explanation:
standard form of a function is f(x)=ab^x
a should be 3, or the y value where the x value is 0
the b value is 1/2 because that's the rate of change
Answer:
Y=3x+12 (its the first option)
Step-by-step explanation:
I did the assignment.
That sequence is not geometric or arithmetic
it is not changing or doing anything it is just remaining the same.
it would be geometric if it was:
1+1-1+1-1+1........
Draw the tape diagram: a long rectangle and divide it into 4 squares in a row.The whole rectangle represents 24 (as a whole number), you're dividing it into 4 parts because you want to know what is 1/4 of it.Now, to find the value of each square: 24:4 = 6.Put the number 6 in each square, and you have found your result.1/4 of 24 is 6.
Answer:
A
Step-by-step explanation:
Given
y - 2x - 8 = 0 ( add 2x + 8 to both sides )
y = 2x + 8 → (1)
y² + 8x = 0 → (2)
Substitute y = 2x + 8 into (2)
(2x + 8)² + 8x = 0 ← expand left side using FOIL and simplify
4x² + 32x + 64 + 8x = 0
4x² + 40x + 64 = 0 ( divide through by 4 )
x² + 10x + 16 = 0 ← in standard form
(x + 8)(x + 2) = 0 ← in factored form
x + 8 = 0 ⇒ x = - 8
x + 2 = 0 ⇒ x = - 2
Substitute these values into (1) for corresponding values of y
x = - 8 : y = 2(- 8) + 8 = - 16 + 8 = - 8 ⇒ P (- 8, - 8)
x = - 2 : y = 2(- 2) + 8 = - 4 + 8 = 4 ⇒ Q (- 2, 4 )
Calculate the length of PQ using the distance formula
PQ = ![\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }](https://tex.z-dn.net/?f=%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E2%2B%28y_%7B2%7D-y_%7B1%7D%29%5E2%20%20%20%20%7D)
with (x₁, y₁ ) = P (- 8, - 8) and (x₂, y₂ ) = Q (- 2, 4 )
PQ = ![\sqrt{(-2-(-8))^2+(4-(-8))^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28-2-%28-8%29%29%5E2%2B%284-%28-8%29%29%5E2%7D)
= ![\sqrt{(-2+8)^2+(4+8)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28-2%2B8%29%5E2%2B%284%2B8%29%5E2%7D)
= ![\sqrt{6^2+12^2}](https://tex.z-dn.net/?f=%5Csqrt%7B6%5E2%2B12%5E2%7D)
= ![\sqrt{36+144}](https://tex.z-dn.net/?f=%5Csqrt%7B36%2B144%7D)
= ![\sqrt{180}](https://tex.z-dn.net/?f=%5Csqrt%7B180%7D)
= ![\sqrt{36(5)}](https://tex.z-dn.net/?f=%5Csqrt%7B36%285%29%7D)
=
× ![\sqrt{5}](https://tex.z-dn.net/?f=%5Csqrt%7B5%7D)
= 6
→ A