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Free_Kalibri [48]
2 years ago
5

Solve each equation, this problem is 60a from the rsm homework

Mathematics
1 answer:
-Dominant- [34]2 years ago
5 0

Answer:

x = -3

Step-by-step explanation:

to solve this equation you should first find the LCD or least common denominator for 2 and 6

the LCD is 6

so you should multiply each side by six

6 * \frac{x + 5}{2} + 6 * -\frac{x + 3}{6} = 6 * 1

3x + 15 - x - 3 = 6

now combine like terms

2x + 12 = 6

now subtract both sides by 12

2x = -6

lastly divide everything by 2

x = -3

that is your answer

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Determine for which values of m the function variant Φ(x) = x^m is a solution to the given equation. a. 3x^2 (d^2y/dx^2) + 11x(d
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Answer:

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Step-by-step explanation:

for

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dΦ/dx (x) = m*x^(m-1)

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then

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for b)

x^2 (d^2y/dx^2) - x(dy/dx) - 5y = 0

x^2*m*(m-1)*x^(m-2) -  x* m*x^(m-1) - 5*x^m = 0

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dividing by x^m

m*(m-1) -m - 5 =0

m² - 2 m - 5 =0

m= [2 ± √(4 + 4*1*5)]/2 = (2±√24)/2 = 1 ±√6

m₁ =  1 + √6 , m₂ =  1 - √6

then Φ(x) = x^m is a solution for the equation b , when m =  1 + √6 or m = 1 - √6

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