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3 years ago

How do you solve 0.8=6-2.5x

2 answers:

6 0

X=2.08

To solve you need to first get x by itself. To do that you want to subtract 6 from both sides (get 6 away from x and put on other side) which will leave you with -5.2=-2.5x next isolate x by dividing -2.5 on both sides to then get 2.08=x

tamaranim1 [39]3 years ago

3 0

Answer:

BEDMAS

Step-by-step explanation:

The order of operations for any and every equation is BEDMAS:

Brackets - none exist here

Exponents - none exist here

Division/Multiplication - "2.5x"

Addition/Subtraction - "+6-2.5x"

When isolating a variable, order of operations is reversed:

Addition/Subtraction:

Move +6 to the left side by subtracting it:

5.2 = -2.5x

Division/Multiplication:

Divide "-2.5x" by -2.5 to isolate x:

x = 5.2/-2.5

x = 2.08

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Element X is a radioactive isotope such that its mass decreases by 59% every day. If an experiment starts out with 390 grams of

miss Akunina [59]

Answer:

The function that represents the mass of the sample after t days is $A(t) = 390(0.41)^t$ .

The percentage rate of change per hour is of -2.46%.

Step-by-step explanation:

Exponential amount of decay:

The exponential amount of decay for an amount of a substance after t days is given by:

$A(t) = A(0)(1-r)^t$

In which A(0) is the initial amount, and r is the decay rate, as a decimal.

Element X is a radioactive isotope such that its mass decreases by 59% every day. The experiments starts out with 390 grams of Element X.

This means, respectively, that $r = 0.59, A(0) = 390$

$A(t) = A(0)(1-r)^t$

$A(t) = 390(1-0.59)^t$

$A(t) = 390(0.41)^t$

The function that represents the mass of the sample after t days is $A(t) = 390(0.41)^t$ .

Hourly rate of change:

Decreases by 59% every day, which means that for 24 hours, the rate of change is of -59%. So

-59%/24 = -2.46%

The percentage rate of change per hour is of -2.46%.

5 0

3 years ago

If $20.00 is for 12.25kg of peas ...what weight of peas can i get for $4.00

Alina [70]

2.45kg

First you calculate the price per kg as follows:

If it’s $20 for 12.25 kg, the price per kg is $20/12.25=$1.63 per kg

If you have $4, you can figure out what weight you can get by taking $4/the price per kg, so $4/$1.63, which is 2.45 kg.

4 0

3 years ago

each Saturday morning Janie works 5 hours and earns $35.75. How much does Janie earn for each hour she works?

bulgar [2K]

Answer:

$7.15

Step-by-step explanation:

You would get this by dividing $35.75 by 5.

8 0

2 years ago

What is the answer to x? Help ASAP

Brut [27]

Answer:

Step-by-step explanation:

2x + 24° = 4x ( being vertically opposite angles)

4x - 2x = 24°

2x = 24°

x = 24° / 2

x = 12°

Hope it will help :)

3 0

2 years ago

Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts

shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0

3 years ago