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3 years ago

Please help! Solve the inequality for x 3(x + 4) > 4 - X

Mathematics

2 answers:

Maurinko [17]3 years ago

6 0

Answer:

x>-2

Step-by-step explanation:

3(x + 4) > 4 - X

Distribute

3x+12> 4-x

Add x to each side

3x+12+x > 4-x+x

4x+12 > 4

Subtract 12 from each side

4x+12-12>4-12

4x> -8

Divide each side by 4

4x/4 > -8/4

x>-2

vichka [17]3 years ago

6 0

Answer:

x>-2

Step-by-step explanation:

3(x+4)>4-x

Do distributive property

3x+12>4-x

Add x on both sides

4x+ 12>4

Subtract 12 on both sides

4x>-8

Divide by 4 on both sides

x>-2

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9900 watts-hours is how much it consumes in a period of 5 days and 12 hours.............to check this: multiply 1800 by 5 and it equals 9000 then you divide 1800 by 2 because 12hours is a half day and it is 900 after all that you add 9000+900 and it equals 9900

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3 years ago

Read 2 more answers

Each output value is equal to the square of the input value minus<br> five

Ivenika [448]

i think that A pair of an input value and its corresponding output value is called an ordered pair and can be written as (a, b). In an ordered pair the first number, the input a, corresponds to the horizontal axis and the second number, the output b, corresponds to the vertical axis.

We can thus write our values as ordered pairs

(0, 0) - This ordered pair is also referred to as the origin

(1, 2.5)

(2, 5)

(3, 7.5)

These ordered pairs can then be plotted into a graph.

6 0

3 years ago

3x + 2y = 12<br> y = x - 9

Lina20 [59]

Answer:

y=12/2

y=6

x=12/3

x=4

y= x-9

Y=4-9

y=5

6=5

6/5

1.2

5 0

3 years ago

Rewrite the expression with rational exponents as a radical expression by extending the properties of integer exponents.

ra1l [238]

The expression will be written as $\rm \sqrt[8]{2^5}$ ., the correct option is A.

<h3>What are Exponents?</h3>

Exponents are the base raised to a power, It is written in the superscript of a number.

The expression given in the statement can be written as

$\rm \dfrac{ 2^{7/8}}{2^{1/4}}$

By the Exponent rule,

$\rm \dfrac{a^m}{a^n} = a^{m-n}$

So the expression can be written as

= $\rm 2^{5/8}$

= $\rm \sqrt[8]{2^5}$

Therefore, in radical form, the expression will be written as $\rm \sqrt[8]{2^5}$ ., the correct option is A.

The complete question is

Rewrite the rational exponent as a radical by extending the properties of integer exponents.

2 to the 7 over 8 power, all over 2 to the 1 over 4 power

the eighth root of 2 to the fifth power

the fifth root of 2 to the eighth power

the square root of 2 to the 5 over 8 power

the fourth root of 2 to the sixth power

To know more about Exponents

brainly.com/question/5497425

#SPJ2

6 0

2 years ago

Show Work Please Thank You

Misha Larkins [42]

Answer:

$\displaystyle{x = \dfrac{\pi}{12}, \dfrac{\pi}{6}}$

Step-by-step explanation:

We are given the trigonometric equation of:

$\displaystyle{\sin 4x = \dfrac{\sqrt{3}}{2}}$

Let u = 4x then:

$\displaystyle{\sin u = \dfrac{\sqrt{3}}{2}}\\\\\displaystyle{\arcsin (\sin u) = \arcsin \left(\dfrac{\sqrt{3}}{2}\right)}\\\\\displaystyle{u= \arcsin \left(\dfrac{\sqrt{3}}{2}\right)}$

Find a measurement that makes sin(u) = √3/2 true within [0, π) which are u = 60° (π/3) and u = 120° (2π/3).

$\displaystyle{u = \dfrac{\pi}{3}, \dfrac{2\pi}{3}}$

Convert u-term back to 4x:

$\displaystyle{4x = \dfrac{\pi}{3}, \dfrac{2\pi}{3}}$

Divide both sides by 4:

$\displaystyle{x = \dfrac{\pi}{12}, \dfrac{\pi}{6}}$

The interval is given to be 0 ≤ 4x < π therefore the new interval is 0 ≤ x < π/4 and these solutions are valid since they are still in the interval.

Therefore:

$\displaystyle{x = \dfrac{\pi}{12}, \dfrac{\pi}{6}}$

8 0

1 year ago