It is now 10:29

1 answer:

8 0

If the question here is Suzette late? Then the answer is:
First hallway: change in t = change in d / v= 35.0 m / 3.50 m/s = 10.0s

Second hallway: change in t = change in d / v= 48.0 m / 1.20 m/s = 40.0 s

Third hallway: change in t = change in d / v=60.0 m / 5.00 m/s = 12.0s
=10.0s + 40.0s + 12.0s = 62.0s
This is 2 s after the bell rings so, Suzette is late again for the third time.

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Select the correct answer.

oksano4ka [1.4K]

Answer: $\dfrac{1}{3}$

Step-by-step explanation:

Favorable outcomes (sum is a multiple of 3): (1,2) , (1, 5), (1,8), (2,1) , (2,4), (2,7) , (3, 3), (3, 6), (4, 2), (4, 5) , (4, 8), (5,1), (5, 4), (5, 7), (6,3), (6, 6).

Number of favorable outcomes (sum is a multiple of 3): 16

Total outcomes = Total outcomes of 6-sided die x Total outcomes of 8-sided die=6 × 8 = 48

Then , the probability of getting numbers whose sum is a multiple of 3:

$=\dfrac{\text{favorable outcomes}}{\text{total outcomes}}\\\\=\dfrac{16}{48}=\dfrac{1}{3}$